Grade

Subject

Type of questions

English Junior High

接続詞です。全然分かりません、上の問題もあってるか分かりません😭😭教えてください

実戦問題 に適する語(句) をア~エから1つ選びなさい。 1 次の (1) The actress is famous not only in Japan ア and but also in the U.S. or I SO yesterday was a national holiday, my father had to go to the office. 7 Although But If I However Jon (3) My grandmother worked as a nurse for thirty years 7 because <if (2) while I until Bill's mother, but in fact she is his grandmother. B was will be I is going to be (4) I thought she 7 is (5) I'll call you after I 7 finish イ my homework. finished will finish I am finishing she was sixty. に適する語を書きなさい。 2 次の各組の文がほぼ同じ内容になるように, (1) It's cloudy tonight, so we can't see any stars in the sky. We can't see any stars in the sky because it's cloudy tonight. (2) [I visited many temples during my stay in Kyoto. I visited many temples I (3) You may cut yourself if you are not careful. careful, you may cut yourself. (4) Though he was very tired, he finished his work. He was very tired, he finished his work. (5) He bought hamburgers. His brother bought hamburgers, too. his brother bought hamburgers. he (3) A: I usually don't have breakfast. B: (early/get/have/ you'll/up/,) enough time. *1 〈中央大附属〉 3 次の 内の語(句) を並べかえなさい。 ただし, (3)4) は不足する1語を補うこと。 (1) A: (about/ hear/I/know/ Japanese history/you/that) very well. B: Yes. It's very interesting to me. (4) A: What are you going to do tomorrow? B: Well, I'll (it /if/ my blanket/ sunny/wash). *1 in Kyoto. 〈拓大第一〉 < 慶應 > 〈西南学院〉 (2) (cell phone / go / in / leave /to/ the living room / when / you/your) school. (★Â) <土佐塾 >

Unresolved Answers: 2
Mathematics Junior High

至急お願いいたします🙇🏻💧 どなたかここの(3)の説明をも少しわかりやすく教えていただきたいです。

4 図のように1辺の長さが8cmの正方形ABCDがある。 点 E. F. Gはそれぞれ辺AB, BC. CD 上にあり、△EFG は,EF=FG, ∠EFG = 90°の直角二等辺三角形である。 次の問いに答えなさい。 (1) ∠BEF=αのとき, ∠EGDの大きさは何度か .αの最 も簡単な式で表しなさい。 (2) ABFE≡△CGFを次のように証明した。 (i) (i)にあてはまるものを、あとのア〜カから それぞれ1つ選んでその符号を書き、この証明を完成させ なさい。 <証明> △BFEと△CGFにおいて, 仮定より, EF = FG ZEBF=4 (i) |=90° △BFE で, 内角の和は180°なので. ア ADG I DGE BFCF.CGIEB=AB+AF E 2 BFE オ EFG B- ∠BEF=180° (∠EBF+ ∠ (ii) = 180° − (90° + 4 (ii)). = 90°- 4 (ii) ...... 3 ∠BFC = 180° ∠ EFG = 90° なので. ∠CFG =∠BFC- (∠EFG+ ∠ (i) = 180°- (90°+ ∠(i)) = 90° - 4 (ii) (4) ④より, ∠BEF=∠CFG ......(5) ②⑤より 直角三角形の斜辺と1つの鋭角がそれぞれ等しいので、 △BFE≡△CGF F ウ CGF 力 FCG D (3) △EFGの面積が最も小さくなるとき, 線分BFの長さは何cmか求めなさい。 (4) 線分FG上を動く点をPとする。 3点C.P.Eが一直線上にあるとき 四角形APGDの面積は 何cm² か 求めなさい。

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