122 α₁=1 α₂ = 2 An+ 2 = An+ ₁ xan
2# (An+ 2)² = Anti An
x
Q
264 - x =
x(x²³²-1) = O
x (x - 1)(x² + x + 1) = 0
X = 0₁1. = 1 = √ 1-4
X₁+¹4da2² X=0₁ |
An+2 - Anti = 0
Au+2 = (An-₁ ·an) =
A₁ = 120+++ A2=2>054
An+2 = √ anti-an, 20
An+2 = (anti-An ) = a√30 1:
2を底とする対数をとると、
199² An= 2 = = log = (ant x α=)
= = log₂an+i+
2
1 + = = = (og₂an
lagzan= bn & pice
but2 = = buti
x²-x
2
x² =
Ibuti shn
辛x
-±=0
2x²-x-1=0
(x-1)(2x+1)=
2
(n=- G₁ (-1)^-1
X=1₁-2
bene 2 - bene! = = = = (banes-ben)
bnti-bn=Cu とおくと
Cu₁s = = = C₂
7 + ===
- 2
= (b₂-b₁) (-1)^²-1
: (log, A₂-109₂9₁) (-)"~/
こ
= (-1)^-1
bu+1 = bn + (-1)^-/
-bn = bit (1) ky
1-1-1-²-291-(-2)^²-²2-²3/1-(-
3
11
=
31-
An = 2³
3
1-
h-