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English Junior High

至急⚠️ 2枚目の答えを教えて欲しいです

Think U 朝美はさらにガンディーについて知るために,伝記を読んでいます。 ? What is the main idea of Gandhi's movements? イギリスで弁護士の資格を得たガンディーは、23歳のときに南アフリカに渡ります lawyer in Gandhi moved to South Africa to work as a 1893. It was under British rule at that time and there was a lot of discrimination. For example, Indians could not go out at night freely or walk on the sidewalk. There were also hotels that did not accept Indian guests. In 1906, the British made a law that was even more unfair to Indian people. Indians in South Africa got angry and stood up against the law. Gandhi decided to lead a movement to protect their rights. His message was "Don't follow the law, but don't use violence, even if you are arrested." Soon the jails became full of Indians, and Gandhi himself was sent there. Finally, in 1914, after many years and much effort, the law was removed. It showed that non-violent movements can be effective. staldis ne 1900 red a lot of people [139 words] 5 A Legacy 10 ガンディーの非暴力のたたかいは、祖国インドでも続きます。 Gandhi returned to India in 1915. India was also a British colony. In those days, there was a law that the British made for salt. According to the law, only the British could produce or sell salt. They put a heavy tax on it. The Indians were very poor, but they had to buy expensive salt. The money went to the British. Gandhi thought it was unfair. S 800 In 1930, Gandhi decided to walk to the sea and make salt himself. He started with 78 followers. Thousands of people joined him on the way. After walking almost 400 kilometers, he reached the sea. This non-violent march was called the Salt March. News of the march spread around the world. It showed people a new way to fight against discrimination. Gandhi's peaceful fight continued after that. In 1947, 15 India won independence. Non-violent protest is the legacy that Gandhi left. It has influenced famous leaders, such as Martin Luther King, Jr. and Nelson Mandela. [161 words / 300 words]

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Mathematics Senior High

この問題の意味は分かるのですが、階差数列の公式がいまいちわかりません。k -1乗だったら、シグマの上のn -1をkに入れて、3のn -2乗になるんじゃないんですか??初歩的な質問ですが、丁寧に教えていただきたいです!!

基本例題 117a.niba.+(n の1次式) 型の漸化式 DE TÚRINA CAMINI PRO ART 4 a=1, an+1=3an+4n によって定められる数列{an}の一般項を求めよ。 基本 116 p.560 基本例題116の漸化式an+1=pan+g の g が定数ではなく, nの1次式となってい る。このような場合は,nを消去するために階差数列の利用を考える。 CHART 漸化式 an+1= pan+(nの1次式) 階差数列の利用 an+1=3an+4n an+2=3an+1+4(n+1) ②-①から an+1-an= bn これを変形すると ① とすると an+2an+1=3(an+1-an) +4 n≧2のとき <a b1+2=a2-a1+2=7-1+2=8 よって,数列{bm+2} は初項 8,公比3の等比数列で n-1 2 bn+1=36+4 bn+1+2=3(6+2) +2=8.31 すなわち bn=8・3-1-2...... (*) an=a+2(8.3k-1-2)=1+ k=1 =4・3"-1-2n-1 ...... ③ 83-1-1) 3-1 00 -2(n-1) ①のnにn+1 を代入する と②になる。 差を作り, n を消去する。 <{bn} は{an}の階差数列。 <α=3a+4 から α=-2 <az=3a+4・1=7 n≧2のとき 7-1 an=a₁ + Σbk n=1のとき 4・3°-2・1-1=1 a=1であるから, ③はn=1のときも成り立つ。 したがって an=4.3”-1-2n-1 (*)を導いた後, an+1-αn=8・3-1-2 に ① を代入して α を求めてもよい。 初項は特別扱い (検討) {an-(αn+β)} を等比数列とする解法 別アプ例題はαn+1=pan+(nの1次式) の形をしている。 そこで, f(n)=an+βとおき, ローチ ① の形に変形できるようにα, an+1=3an+4n が, an+1-f(n+1)=3{an-f(n)} β の値を定める。 ①から ゆえに an+1-{a(n+1)+B}=3{an (an+B)} an+1=3an-2an+α-2β これと an+1=3an+4n の右辺の係数を比較して -2a-4, a-28=0 って α=-2, β=-1 ゆえに f(n)=-2n−13.0=20 ①より、数列{an- (−2n-1)} は初項α1+2+1=4, 公比3の等比数列であるから an-(-2n-1)=4・3-1 したがって an=4.3" 1-2n-1 563 +X 3章 117 = -2, an+1=-3α-4n+3によって定められる数列{an}の一般項を求めよ。 6135 1619 15 5 漸化式と数列

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