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English Junior High

なぜ、答えが『ウ』 ではなく『イ』なのか 教えてほしいです🙇‍♀️

次の英文を読んで、問1~問5に答えなさい。 *印のついている語句には,本文のあとに〔注〕があります。(10分) A 1901, the Nobel Prize has *honored men and women from all over the world for great work in science, writing, and peace. The Nobel Prize is an *award that was started in Sweden. The name Nobel Prize comes from a Swedish scientist, Alfred Nobel, who made more than 350 *inventions. In 1895, a year betore he died. he set up the award. Many people think the Nobel Prize is the greatest award a person can receive. Twenty two people from Japan have received the Nobel Prize. Recently, awards were given to three scientists from Japan in 2014 (for their work in science. These three scientists, Isamu Akasaki, Hiroshi Amano, and Shuji Nakamura, made a bright blue *LED in the 1990s. All three colors are needed to make a white LED. White LEDs are bright, last for a long time, and don't use much *energy. Because of this, white LEDs are becoming more and more popular. They are B than fluorescent lights or *incandescent lights, but people can use them for a longer time. People can use LEDs for about 100,000 hours. That is 10 times as long as people can use fluorescent lights and 100 times as long as people can use incandescent lights. (2 Perhaps you are thinking that these scientists are cleverer than you. Their invention is really special, but they are people just like you. (3) People said that they could not do it. They had to make their own *equipment for their work. they tried more than a thousand times, they still were not able to make a blue LED. But they never gave up and finally they did it. Perhaps one day, if you work hard, you will get the Nobel Prize, too. Nobel Prize ノーベル賞 award LED I'I ・発光ダイオード 蛍光灯 機器 ……………. fluorescent equipment 〜をたたえる 発明品 honor invention energy I: incandescent 白熱灯 .…....

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Physics Senior High

青線の部分を計算しても答えがでません。途中計算を教えてください。全然合いません答えが

N サー41 ナー42 を質量 して考 ・2d. 考え ( L-L 153 別解 初めてx=dとなるときに物体Bが物体Aから離れる から (2) の結果より (2) P: よって、 (1) L-200 4 g d= -2d cos 2d 2π となるから, t= t= 3 /2m V 3k Vo √3k 12m 3k 2 g /2m [m] t ゆえに COS (m), Q: [s], Q: 2π 2 /2m ・200 3k 2 3 /2m (2) 求める P Q の単振 動の振幅をそれぞれ Ap[m], AQ〔m〕 とする。 運動を始めたとき,P, Q はともにつり合いの 位置にあり, ばねが最 も縮んだとき,P, Q は重心Gに対して静 止する。 P, Q の質量 の比は1:2より,ど ちらの場合もGはPQ を2:1に内分する点 となるから, Ap= Vo 12m ✓ 3k /2m 3k [s] [m〕 OH P 27T (3) P: 27 指針 (1) 外力による力積が加わらないため, つながれた小球P Q の重心Gは等速直線運動をする。 ばねが最も縮んだとき, P, Qの速度 は重心の速度に等しくなる。 (2), (3) P, Qは,重心に対して単振動する。 g 2d Ap 3 √ 解説 (1) 右向きを正とし, ばねが最も縮んだときの小球 P, Q の速 (1) 度をV/[m/s] とする。 運動量保存の法則より, mvo+2m(vo)=mV+2mV Vo これより, V=- 3 求めるばねの長さをL'[m]とすると, 力学的エネルギー保 存の法則より, m² +2m² = k (L-1)³ + ½m-3) •2mv²= k(L-L')² t = - 2d g ゆえに,I'=L-200 '[m] (L'は不適) √ 3k L -[s] 1 2 2 of color and + 12.2m ( - 20/0 3 12/2300 ammino L' 002 (53) センサー41 ●)) センサー 42 AQ つながれた小球P. Qの重心の速度を v[m/s] とすると c =Vである。 G は水平左 向きにの速さで等速 直線運動をしている。 10

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