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English Senior High

丸のついたandについて質問です。andが結びつけているものは何かという問い対して、前後の二文全部だと思ったのですが、high~valueまででした。どういうことでしょうか?

By Theresa Cooper, Pittsburgh, PA 12 October 2019 2:14 PM Pittsburgh schools are considering switching from traditional paper textbooks to e-books within the next few years. In order to read their e-books, students will be required to buy tablets at reduced prices from the school district. This policy would affect junior and high school students over the age of 12. The head of the Pittsburgh school district, Evan Ng, said, "We're trying to stay up to date with technology. We've also had many complaints about the high cost and low resale value of textbooks over the years, and buying a single low-cost tablet will save families hundreds of dollars within 2 years." He went on to say, "Furthermore, this will help students avoid back problems that can arise from carrying heavy textbooks around in their backpacks all day." (5) Patrick Roth said, "All this technology is starting to get out of hand. Don't students already spend enough time looking at screens? This seems like it could harm their vision." One HT (Clayton Thebe parent suggested, "Even with restrictions, these tablets will be just another distraction for the kids. My kids already have trouble finishing their homework as it is." 43 Comments bnoga (1) B Newest Jeill IT

Unresolved Answers: 1
English Senior High

(4)を訳したいのですが、文構造が分からずうまく訳せません、。どなたか解説をお願いします。

lo One fast-food company is well known in Japan for its extensive worker manual and the sales talk it covers. From the book, workers learn how to greet a customer, how to bow, how to take an order, pack a bag and give correct change. 5 Customers find the same nice service in all the franchised outlets, which contributes to both customer satisfaction and *corporate profits. One day, a mother came into one of these restaurants, and while she was ordering at the counter, her baby grabbed an 10 employee's hat and began to play with it. He was surprised and embarrassed. He could not concentrate on what the customer (2) was saying and had to ask her to repeat her order twice. He knew he was losing his dignity as a company representative by having an infant tearing up part of his uniform, and he wanted to 15 take it back, but at the same time he didn't know what to say or do. He stood there ( 3 ) until the mother *retrieved the hat and gave it back to him. He put it on again, resumed his normal calm attitude, and took her order efficiently as if nothing had happened. But everyone in the restaurant could see that a 20 one-year-old child had the power to bring the operation to a halt and must have wondered about it. What was the problem here? Simply put, the manual, detailed as it may be, fails to cover what to do in a situation where a young child steals part of your uniform. And without the manual to guide his behavior, the employee was lost. This is a trivial example of a very serious problem in Japan: the inability to 48

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Mathematics Senior High

数学数列  画像の四角で囲ったところのように変形するのはありですか?無しであればその理由を教えてください。

「つ」 306 308 数学的帰納法 〔3〕 ... 不等式の証明(2) 4以上の整数とするとき, 数学的帰納法を用いて次の不等式を証明せよ。 2" <n! 自然数nについての等式、不等式の証明は数学的帰納法を考える。 味の言い換え [1] n=4のときに ① が成り立つことを示す。 ( ① の左辺) (①の右辺) [2] 「n=kのときに ① が成り立つと仮定すると, n=k+1 のときにも ① が成り立つ」 ことを示す。 n=kのときの不等式 2 < h! が成り立つと仮定。 ⇒n=k+1のとき n=4 をそれぞれに代入して (左辺) (右辺) を示す。 (k+1)! -2k+1 = (k+1)k!-2k+1 > (k+1)-2+1 = ... > 0 仮定の利用 <<Action 数学的帰納法では,n=k+1 のときの式の複雑な部分に仮定の式を用いよ [1] n=4のとき (左辺) = 24 = 16, (右辺)=4!= 24 左辺) (右辺)であり, ① はn=4のとき成り立つ。 [2] n=k(k≧4) のとき, ① が成り立つと仮定すると 2<k! n=k+1 のとき (右辺) (左辺) (k+1)! - 2k+1 = = (k+ 1)k! - 2k+1 > (k+1)22k +1 =2^{(k+1)-2} k≧4であるから nは4以上の整数である。 =2(k-1) 2^(k-1)>0 2k+1 < (k+1)! よって ゆえに, ① は n =k+1 のときも成り立つ。 [1],[2] より,4以上のすべての整数nに対して成 り立つ。 4以上の整数について命 題が成り立つことを証明 する場合は,まず [1] と してn=4のとき成り 立つことを示す。 特訓 2 例題 306 (右辺) (左辺) > 0 を示 す。 仮定した不等式を用いる ためにk! をつくる。 (k+₁) £! - (2² > (E11) 21-1-2 (7-1) £! 308nが4以上の整数とするとき, 次の不等式を証明せよ。 3n > n³ ... 1 6章 化式と数学的帰納法 条件 k≧4 を忘れないよ うにする。 18 (宇都宮大) p.519 問題308 509

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Mathematics Senior High

数1の問題です (1)で「√2が無理数であることに矛盾する」の後にb=0を導き出せるのかが分かります よろしくお願いします🙇

例題 55 背理法による証明 〔2〕即痛さも [2]] 思考のプロセス α, bを有理数とするとき、 次の問に答えよ。 ただし,√2が無理数であ ことを用いてもよい。 (1)a+6√2=0 ならば a = 0かつ6=0 であることを示せ。 α(1+√2)+b(2-√2)=4+√2 を満たす α, bの値を求めよ。 (2) (1) 「a+6√2=0」から直接「α = 0かつ6=0」 を導くのは難しい 背理法 目標の言い換え矛盾をどこから導くか? を用いることに注意すると 条件 「 √2=-1と変形して(無理数) = (有理数)となり矛盾」としたい。 ■ 「α≠ 0 または 60」を仮定する必要はなく、 「60」 を仮定するだけで十分。 Action » 結論が 「p かつα」の背理法は, (またはg) のみを仮定せよ 解(1) 6≠ 0 と仮定する。a+b√2=0 より √2 (2) a a,bが有理数であるから, -1 は有理数である。 b これは,√2が無理数であることに矛盾する。 よって b=0 これをa+6√2=0 に代入すると したがって, α, 6 が有理数のとき 2 = a=0 a +6√2=0 ならば α = 0 かつ b = 0 alld 1/0 ★☆ b 結論の一部 b=0 して矛盾を導く。 (有理数) ÷ (0 でない有 = (有 b = 0 のみを仮定 矛盾を導いたのであ ら,得られる結論 のみである。

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