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English Senior High

誰か教えて欲しいです!!英語本当に苦手で、、、。大至急です!!お願いします🤲

問題 001 ~030 目標時間:3分20秒>1問 20 )に入れるのに最も適当な語(旬) を, 下の0~④から1つずつ選びなさい、 ) for 30 years. 2 次 口 001 The man missed his hometown, which he ( 4 does not see 1次の問いの ( 2 has not been seeing ロ0 1will have not seen 口 002 I'm afraid I left my pen in my office. Do you have something to write ( の by 3 had not seen の for (青山学院大 3 with 2 to 口 003 The time will come ( ) you will understand what I am saying. 3 when ④whether (亜細亜大 ① where 2 which 口 004 A: How was Helen's concert? B:The audience was very ( ) to see her singing and dancing. の funny (学習院大 モーー ) she should be upset about everything 2 exciting 大③ fun の excited 005 We don't particularly ( 2 think odd 1 think it odd that の think oddly that (図撃院大 3 think odd that コ006 The child found the purse ) near the bench. 3 to lie 0000 1S lying (駒毒大) aituOX 西00 のlie 2 lying 007 I definitely saw my brother (0=) hand in hand with your sister. O having walked 2 to have walked 3 to walk ④walk M%3D回0) (上智大) 08 ( ) did I know that the course of my life was about to change at that time. O Less 2 Little 3 Lots の Much (学習院大 9 I'm surprised that you went there. ( ) don't visit that part of town. O Most of tourists 2 Most the tourists 3 Most tourists の The most tourists ロ

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Mathematics Senior High

写真の波線部が成り立つのはどうしてですか? 詳しくお願いします!!

家の g tn 例題270 三角形の重心 AABC において, AB, AC の中点をそれぞれ D, Eとし, Dを通り BE に 平行な直線と,Eを通り AB に平行な直線の交点をFとする。このとき、 点EはACDF の重心であることを証明せよ。 逆向きに考える 結論「Eが△CDF の重心」を示すためには? ACDF の中線がEで交わる。 [CG が△CDFの中線 (FHがACDF の中線 → FG:GD = 1:1 E → CH:HD = 1:1 H FG, GD や CH, HD を含む。 AXを考える。 B Action》 重心は, 中線の交点であることを利用せよ 解 AE と DF の交点をG, EF と DCの交点をHとする。 BD / EF, BE / DF より, 四角 形BEFD は平行四辺形であり, AD = DB であるから 4重心は,3つの中線の交 点である。△CDF にお いて,CG, FHが中線で あることを示す。その交 点がEである。 E EM:A 8:D Ga 8AA -0太 266 H AD = DB = FE B AD / FE であるから FG:GD = FE:AD = 1:1 ACAD において, EH / AD, CE = EA であるから M:AM aM 266 F AM-03:94 IG. CH:HD = 1:1 . 2 D D, ② より, CG, FH は △CDF の 中線であるから,点Eは△CDFの 重心である。 (E i H BC F D. G. (別解) B GABS C 5a: (FG:GD = 1:1 …① までは同じ) 点 D, Eがそれぞれ辺 AB, ACの中点であるから, 中点 連結定理により よって,CD とBE の交点をIとすると E DE / BC, DE: BC =D1:2 DI:IC = DE:BC =1:2 に注目する。 IE / DG であるから CE:EG = CI:ID=2:1 GA LAS 2) 0, 2より,点Eは△CDFの重心である。 に注目する。 OA<BA 0OS 練習270 平行四辺形 ABCD に十1 思考のブロセス」

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English Senior High

BとDを教えてほしいです

Suppose you were asked to participate in a blind taste-test of five different brands of strawberry jam. After tasting all of the jams, but before being asked to rate their quality, you spend a couple of minutes ( I 1 ) down your reasons for liking and disliking each jam. Then you rate each one on a scale from 1 to 9. How accurate would your ratings be, assuming we judged accuracy by comparing your ratings with those given bya panel of experts assembled by Consumer Reports magazine? When psychologists Timothy Wilson and Jonathan Schooler conducted this experiment with college students as their subjects, they found that the ratings the students gave to the jams had almost no resemblance to , those given by the experts. 2 They should have been able to tell which ones were good and which ones were not the jams varied widely in quality and included those ranked 1st, 11th, 24th, 32nd, and 44th best out of 45 that Consumer Reports had reviewed. Did the students have no taste for jam? Did their preferences differ from the experts'? Not at all. In a separate condition of the experiment, rather than writing the reasons they liked and disliked each jam, each subject wrote about something entirely ( 4 ): their reasons for choosing their college major. The subjects then rated the jams, and despite not having thought about them at all after tasting them, they made ratings that were much closer to those of the experts.

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