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English Senior High

英文がわからないです心の優しい方、英文の解き方を教えて欲しいです🙇‍♀️

35 15 20 signatures in business. However, no one used fingerprints in crime work until the late In ancient times, people used fingerprints to identify people. They also used them as 1880s. Three men, working in three different areas of the world, made this possible. (1) The first man who collected a large number of fingerprints was William Herschel. He worked for the British government in India. He took fingerprints when people (7) official papers. For many years, he collected the same people's fingerprints several times. He made an important discovery. Fingerprints do not change over time. At about the same time, a Scottish doctor in Japan began to study fingerprints. Henry Faulds was looking at ancient Japanese pottery* one day when he noticed small It occurred to him that the lines were 2,000-year-old fingerprints. Faulds wondered, "Are fingerprints unique to each person?" He began to take fingerprints of all his friends, co-workers, and students at his medical school. Each print was (). He also wondered, "Can you change your fingerprints?” shaved the fingerprints off his fingers with a razor to find out. Would they grow back lines on the pots. (2) He the same? They did. One day, there was a theft in Faulds's medical school. Some alcohol was missing. Faulds found fingerprints on the bottle. He compared the fingerprints to the ones in his records, and he found a match. The thief was one of his medical students. By examining fingerprints, Faulds solved the crime. Both Herschel and Faulds collected fingerprints, but there was a problem. It was very difficult to use their collections to identify a specific fingerprint. Francis Galton in England made it easier. He noticed common patterns in fingerprints. He used these to help classify fingerprints. These features, called "Galton details," made it easier for police to search through fingerprint records. The system is still in use today. When 25 police find a fingerprint, they look at the Galton details. Then they search for other fingerprints with similar features. (4) Like Faulds, Galton believed that each person had a unique fingerprint. According to Galton, the chance of two people with the same fingerprint was 1 in 64 billion. Even the fingerprints of identical twins are ( ). Fingerprints were the perfect tool to 30 identify criminals. For mo than 100 years, no one found two people with the same prints. Then, in 2004, terrorists (I) a crime in Madrid, Spain. Police in Madrid found a fingerprint. They used computers to search databases of fingerprint records all over the world. Three fingerprint experts agreed that a man on the West Coast of the United States was one of the criminals. Police arrested him, but the experts were wrong. The man was innocent. Another man was (). Amazingly, the two men who were 6,000 5 10 136 Lesson 日本大学 470 words 22 (3) 23 024 25 26

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Mathematics Senior High

至急です!! 蛍光マーカーがついたところなんですが、 最大値が 1 最小値が-√2 になるのはなんでですか?

at 1 基本例題156 三角関数の最大 最小 (3) ・・・合成利用 1 次の関数の最大値と最小値を求めよ。 また, そのときの0の値を求めよ。 ただし, とする。 8200+n (1) y=cos-sin 0 指針 前ページの例題と同様に, 解答 また,0+α など,合成した後の角の変域に注意 する。 (2) sin (0+ Cox) のままでは, 三角関数の合成が利用できない。そこで,加法定理を利用 して, sin (9+x) を sine と cose の式で表す。 (1) cost-sin0=√2 sin0+ (2) 同じ周期の sin と cos の和では, 三角関数の合成 が有効。 ゆえに 0+ OMOSTであるから 3 よって1sin(01/27) 2017/1 0+ -√7/2 すなわち 0=0で最大値1 3 4 ゆえに 0+ √2 sin(0+³) ・π 3434 九= 3 4 OMOであるから 7 3x=0+ 3x = -1/1 ≦ π 4 3 π= - すなわち 0 = で最小値-√2 2 (2) y=sin(0+5)-cose 6 3 2 5 *cos0=sinocosm+cos Osin- 6 4 41 √3 2 5 6 √3 -sin0+ ・cos o-cos o 2 2 -sin0- (1) y=sin 0-√√3 cos 0 1 2 πCOSO 7 7 (n=0+ 1x≤ 13³1 π 6 6 -15sin(0+1)=1/ 7 13 0+ π三 - すなわち 0=™で最大値 6 6 2 cos0=sin(0+1) -T-cos (5) 基本154 7 0+ |九= すなわちで最小値-1 6 (-1,1) I √3 I 1 yA √√2 0 y41 6 7. 4 AO 1 6 (-4,-1) y 1 |1 √2 /1x AY 0x 1x Of 13 練習 次の関数の最大値と最小値を求めよ。 また,そのときの8の値を求めよ。ただし, rat © 15600とする。 (2) y=sin(0-5)+sine CELEX 100 245 章 7 三角関数の合成 4章 27

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Mathematics Senior High

cosθ−sinθ=1/2のsinθ、cosθのどちらかに1−○^2をぶち込んで解いていくことはできますか?

146 = 花の等式と式の値 10°≧0≦180° とする。 cos O-sin=1のとき, tan0の値を求めよ。 例題 かくれた条件 sin"0+ cos'0=1 を 連立させて, sino, coseの値を求める。 tan の値は sine, cos 0 の値がわかると求められる。 そこで, 与えられた関係式と CHART 三角比の計算 かくれた条件sin²0+cos²0=1が効く ゆえに 1/1/3から 2 coso-sino= ① を sin'0+cos20=1に代入して 2 sin²0+ (sin0+)²=1¹ 3 2sin20+ sin0- =0 4 よって 8sin20+4sin0-3=0 これを sine の2次方程式とみて, sin0について解くと sin 8= cos0=sin0+ 1/2 -2±√22-8・(-3) 2 -2±2√7-1±√7 = 8 □≦sin 0≦1 であるから sin = このとき, ① から 1 cos o cos0= sin0 COS A 8 −1+√7 4 −1+√7 1 4 =1+tan²0から 1 2 cos 0 =2(1-tan0) + = 2 たがって tan0= 0=90° は与えられた等式を満たさないから 090° よって, cos0=0 であるから, 等式の両辺を cose で って 1-tan0= 1 S²0 埋すると 3tan²A-8tan A+3=0 4 -1+√73) 4-√7 1+√7 3 1+√7 4 4(1-tan0)^=1+tan²0 1) sine を消去して cose について解くと cos 0= 1±√7 4 1-√7 4 は, sino=cos - 1/12/2 -1-√7 4 このうち cos0= x= 基本 144 <0 となり さないが,この判断を見 すこともあるので, COS 3) の消去が無難。 2) 2次方程式 ax2+26′x+c=0の解は = となる。 -1+√7 1+√7 -b'±√√b²-ac a (√7-1)² (√7 +1)(√7-1) 6 8-2√7_4-√7 = 4) tan 3

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