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English Senior High

(21)の答えが3になるのがなんでか少し分からないです…わかる方いますか??

(21) (22) (23) Any Change? Long ago, humans did not use money. Because they often could not produce everything that they needed, they traded some of their goods for goods made by others. Gradually, the goods that they exchanged were replaced by cash. For hundreds of years, metal coins and paper bills that can be exchanged for goods and services have been produced. Cash is convenient for many people because it is easy to carry. At the same time, though, it ( 21 ). Another disadvantage is that criminals have been able to produce fake coins and bills. In the middle of the 20th century, plastic credit cards were introduced. They had security features to prevent them from being used by anyone except their owners. At first, their use was limited to wealthy people. Over time, however, they became ( 22 ). In the last few years, apps for smartphones that can be used in the same way as credit cards have also become popular. Because of this, some people are suggesting that we may soon see the end of cash. Supporters of a "cashless" society in which all payments are made electronically argue that it would have several benefits. For example, people would not have to worry about keeping their wallets safe. However, some people are concerned that they might be unable to pay for the things they need because of a software error or a broken smartphone. Moreover, some people do not have bank accounts or credit cards, so their only option is to use coins and bills. ( 23 ), it seems as though societies will continue to use cash. 1 can be lost or stolen can be recycled 1 thinner and lighter 3 harder to use 1 For now 2 Until then 2 4 2 4 3 is used for shopping online is understood by almost everyone more colorful and exciting more widely available With luck 4 By contrast

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Mathematics Senior High

数列 al=bm…以降の解き方なのですが、l,mの整数解が違うからか答えが全然同じになりませんでした。 模範解答の整数解しか条件を満たさないのでしょうか? 解説お願いします。

Example 44 ***** 1つの実数がある。を初頭… を公差とする等差数列をを を公差とする等差数列を(b)とする。 いま数列 (17²) の第2項がα-8で あり、数列(b)の第4項がb-14 であるとする。このとき、 の値は カッターである。また、このとき2つの数列 (an) と [6] 共通 して現れる数を小さい順に並べて新しい等差数列{cm) を作ると,{cm) は公差はである。またAcadの初項から第n項まで の式で表すとである。 解答 α=p+(n-1)g、bm=g+(n-1)p 8 から p+q=8 3p+g=14 ****** 共通な項を α = bm とすると b=14 から ① ② を解いて p=73.g=15 ① - (9 α=3+5(n-1)=5n-2 b²=5+3(n-1)=3n+2 5.(-1)-2=3· (−3)+2 ③ ④ から 5と3は互いに素であるから l=k-1(k≧1) 51-2=3m+2 4 5(+1)=3(m+3) ****** 1+1=3k(kは整数) ■頃までの和は、 [類 13 関西学院大] key α = bm を満たす を求める して Cn=α3n-i=5(3n-1)-2=15n-7 key 等差数列の和 ゆえに、数列{cm} は初項 "8, 公差 -15 の等差数列である。 答 等差数列{an}の初項か よって、数列{C}の初項から第n項までの和は ら第n項までの和 S は \n(c₁+c₂)=n(8+(15n-7)) = n(15n+1) S₁= n(a₁ + a) Sn²

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