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English Senior High

仮定法の範囲です 6〜21、20、24〜26の答え教えてください! 解いたのであってるかみてほしいです。不正解の場合正しい回答もしりたいです🙇‍♂️

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English Senior High

教えてください!!

PAR Review 5 (Point 131~157) to smo r ■ QAZ- GREL 131~157) 形容詞の語法, 副詞の語法,比較 ETC 英文中の空所に入る適切な語または語句を選択肢から選びなさい。 2. There was hardly ( 1 more 1. Many students were not able to solve the problem, but ( ents wer 1 few ble to so 2 a few 3 little 3. Ken didn't work as ( 1 hard 3 hardest 4. He has a great ( things usd 1973 7. Your plan is ( 17. Ⓒ less do ) rainfall in that area of the country. 2 some 3 no 4 any slɔ od ai (-) ant eslood om hans and sil2 (dytas) ) were. O TOC Besides ) of knowledge about languages. sie o 2 deal 3 quality 形容詞の語法, 副詞の語法, 比較 viilsup ai ) as his brother, and he failed in the final exam. es dou 3 pleased *080 6. Ellie has to finish her project by next Monday. boss. 1 Except ) better than mine. 12 far to excite 5. The singers seemed a little too () with their success. be pleased 2 be pleasing July 11. The news was (\) to us. 21. Ⓒsurprise 2 more seriously 4 many serious 2 excitement PILN 2 surprised on bed anellob svit 4 a little 3 more 10. The school is strict about hair styles; ( (1 moreover 2 otherwise 3 Additionally (B2), 4 ) (0) die Gl and number gaigbulafe 3 surprising TOXOX bubong eidT) Vino 4 too 4 Otherwise 131 (東海大) um coM as 146 blaw edi buona 〈 名古屋学院大 > Har \ gad) 本日132 4 pleasing 〈 近畿大 > 185 she will get in trouble with her 8. A friend of mine is coming to Japan next month. I am very ( ) about the news. ➡132 1 excite (3) excited 4 exciting <東海大 > LOW LAW 304 3 exciting 4 excitable 1940 inging yM AUTO ), some students break the rules. 3 nevertheless 4 notwithstanding ro sniqgsH 9. By the time it ended, our team had battled hard and finally won. The game was indeed ( ). 10 excited 142 ➡131 <杏林大〉 ② 次の英文の 1. Count day. 4 to surprise JanoviaU bolx0 144 < 南山大 > 150 1) I bsando gli om man soad sms I asdW <玉川大〉 132 〈北里大〉 145 〈法政大> 132 <京都学園大 > REST ③ 次の日本 01. 1 Sh 2. Of 3. Alice □ 2. そ C ☐ 3. □ 4.

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Mathematics Senior High

この問題で、延長線を使わなくてはいけない理由はなんですか?仮定で、△ABCの辺BCをAB:ACに内分するって言っているので、∠Aの二等分線⇒BP:PC=AB:ACが成り立つからAPは∠Aの二等分線である、という証明ではダメなのですか?

000 Sluts ABCの辺BC を AB : AC に内分する点をPとする。このとき, APは∠A の二等分線であることを証明せよ。 例題 72 角の二等分線の定理の逆 問題文の内容を式で表すと,次のようになる。 指針 p.448 基本事項 2 定理1(内角の二等分線の定理) の逆である。 BP: PC=AB: AC ⇒ APは∠Aの二等分線 ( ∠BAP=∠CAP) △ABCにおいて、辺BAの延長上に点D ACAD となるようにとる。 つまり, 線分の比に関する条件から, 角が等しいことを示すことになるが, 線分の比を 扱うときには,平行線を利用するとよい。 ∠Aの二等分線BP : PC=AB AC の証明 (p.448 解説)にならい, まず辺 BAのAを越える延長上に, AC=AD となるような点Dをとることから始める。 別解 ∠Aの二等分線と辺BCの交点をDとして, 2点P, D が一致することを示す。 なお、このような証明方法を同一法または一致法という。 p.453 における三角形の重心の証明でも同一法を用いている。 ゆえに SISAKOLA Camar BP:PC=AB:ACのとき, BP : PC=BA : AD から平行線と線分の比の性質 AP//DCを三角形の重心と の逆 ∠BAP=∠ADC ∠PAC=∠ACD ACAD から ∠ADC=∠ACD よって ∠BAP=∠PAC すなわち, APは∠Aの二等分線である。 別解 辺BC上の点Pが BP: PC=AB:AC B P AB:AC=BD:DC BP:PC=BD:DC DI を満たしているとする。 ∠Aの二等分線と辺BCの交点をDとすると, 内角の 二等分線の定理により TOP p.448 基本事項2 ② あ CHURCO AS IMAG ROCLAAS TÄ したがって, APは∠Aの二等分線である。 HOA B ONOTRE 平行線の同位角、錯角は それぞれ等しい。 MAS △ACD は二等辺三角形。 ①②から 6. FADLOWE よって,PとDは辺BCを同じ比に内分するから一致す 同一法 る。 DP C 451 GROMAE CÓRKA 704 が成り立つ。下の練 3章 3 1 三角形の辺の比、五心

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