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English Senior High

この空欄に共通語を入れないといけないんですけど分からないのでよろしければ全部じゃなくても良いので手伝っていただきたいです💦

(3) (a) We must keep an ( ) on the political situation. (b) She hit him hard and gave him a black ( ). (4) (a) This is going to cost you a good ( ) of money. (b) In this African town, there are many merchants who ) in diamonds. (5) (a) That politician always takes a strong () on difficult social issues (b) He was so shocked by the news that he could hardly ( ) up. (6) (a) Why are you sitting so far ( ) from us? Come over here and join us. (b) The two brothers look so much alike that it is difficult to tell them ( ). (c) The dog has pulled the newspaper ( ) again! (d) I don't like to mix business with pleasure, but try to keep the two things firmly ( ). (8) (a) In my ( ) you should try the exam again. (b) The ( uldn't got (7) (a) () all his campaigning, he couldn't get enough votes to win. (b) It might be better for us to make allowance ( ) his inexperience because he is a newcomer. (9) (a) You will be sure to like him, ( ) you talk with him. (b) He writes a letter ( ) in a while, but not so often. The earth goes around the sun ( ) a year of 251) (10) (a) A( ) from the mountain top was spectacular. ) is a place where you can get water. (b) The doctor said that he would be ( (11) (a) Will you ( 15 (c) He has knowledge and experience as ( ). ) if he took this medicine. ) after the children while I'm out? in the long run 結局は (b) ( ) in the mirror before you drive off

Solved Answers: 1
Mathematics Junior High

この問題の(4)の解説で △PBC:△PDC=3:2=9:6 その下の同様にして...の後の比もどうしてこうなるのか分かりません 教えて頂きたいです

5ACDG = 12AAEF 右の図のように, AD // BC の台形ABCD で, 対角線の交点Pを通りBC に平行な 直線をひき, AB, DC との交点を, それぞれ,Q,R とする。 -6 cm-D (1) APDAS APBC であることを証明しなさい。 APDA E APBCで、 AD//BCから、平行線の錯角は等しいので、 LDAP = LBCP-0, LADP = <CBP--- ①.②から、2組の角がそれぞれ等しいので、△PDA APBC (8) (2) PQ QR の長さを求めなさい。 AD//BC S. AP: CP= AD: BC= 6:9=2:3 (3)). APDA: APBC = 4:9 ··-0 対頂角は等しいので ZAPD=LCPB 20 AAEF: ACDG= 1/2/2/2/2 Lhp ABCD: APBC = 25:9 9xABCD= 25APBC AABCT QP// BC FPY. ACADT PR/AD TAY. Pa CB = AP: AC > 5PQ=18 PQ: 9 = 2:5 S 12 = 4 & cm (36) PR : 6 = 3: 5 PRAD= CP:CA PR=4cm - 36 (3) APDAとAPBCの面積の比を求めなさい。 また, APBC と APDCの面積の比を"cm 求めなさい。 th. APBC & APDC 7.222 (7.2cm) 辺PB.PDを底辺とすると、高さが等しいので、 APDAMAPBCで相似比は2:3だから. 面積比は2:3=4:9 1 PB & PD q ce izg APDA: APBC= 47 APBC: APDC = PB: PD = PC: PA = 3:2 (4) 台形ABCD の面積は、 △PBCの面積の何倍になるか求めなさい。 B SCOOT APBC APPC= 3:2 = 9:6 2 同様にして、△PDA:△PBA=2:3=4:6.③ 0.Q.F). APDA: APBC: APDC : APBA = 4:9:6:6 STAB CD = 2 APBC: 25 -1/2 倍 5 PR=18 を証 =5:12 鍋 -9 cm- 01. 17 4+9+6+6=25 QR-PQ+ PR = 1/2+1/2/20 APDA= 4a E APBC=9a 218ppc = ba APBA = 6a ABCD = 40 +9a+ba+ba 25a ABCD: APBC=25

Solved Answers: 1