Grade

Type of questions

English Junior High

本日、投稿し直します! 今日こそ、これを教えてくれる人、来て~!(ガチでへるぷみー)

【7】 次の英文の空所に入る適切な単語 (前置詞) を書きなさい。 Most of us are interested ( ) science. He is very good ( at ) speaking English. Suma is famous ( ) its beautiful beach. Wine is made ( The top of the mountain is covered He is looking forward ( We were much surprised ( I got a letter written ( Please take ( (1) (2) (3) (4) (5) 次は、 前置詞の穴埋め問題 ・・・ 覚えた連語や文法が役立ちます (6) (7) (8) (9) ) grapes. (10) The basket is full ( (11) They don't work ( (12) These shoes are too big ( (13) I can swim fastest ( (14) Tom read books about Japanese (15) I usually drink coffee ( (16) This desk is made ( (17) Ken is very fond ( (18) Yuki takes care ( (19) My mother was born ( (20) Don't be late ( (21) How ( (22) Arisa took part ( (23) It is difficult ( (24) Why were you absent ( ( (25) I have lived in Nagoya (26) His name was known ( (27) Thank you very much ( (28) Have you ever been ( (29) February is ( (30) Tuesday comes ( (31) ( ) seeing ) English. ) your shoes when you enter a house in Japan. ) beautiful flowers. ) Sundays. ) ) snow. you. ) the news. ) me. ) all the boys. history ( ) sugar. ) wood. ) listening to rock music. ) this cat. ) school. ) taking a walk around here ? ) morning till night. ) January 28th, 1975. ) the festival last year. me to get up early. ) school yesterday? ) a long time. I must finish this English homework ( ) everyone. ) inviting me to the party. ) Singapore ? ) January and March. ) Monday. ) next Monday.

Unresolved Answers: 1
Chemistry Senior High

なぜ、2つの式が必要になるのでしょうか? 赤で線引いた所です。

の表か のです。 E, (必須問題 入試攻略 C [mol/L] の弱酸HA水溶液の全水素イオン濃度を[H+] [mol/L], 酸 の電離定数を Ka, 水のイオン積を Kw とし, [H+] を求めるための方程 HAI 式を求めよ。 y HA H2O Ka ←H+ + A Kw Can H+ + OH OD まずは厳密に解いてみましょう。 [HA],[A-], [H+], [OH-] の4つが変数 なので、 ① 式と②式以外にあと2つの式が必要となります。 (i) 原子団Aに関する保存則 __c = [HA] + [A] ... ③ (ii) 電荷の保存則 総正電荷 H.CO. Kw ②式より, [OH-]=[H"] これを④式に代入して, [H+]x1 = [A-]×1 + [OH-]×1 総負電荷 これを③式に代入して, [H][A] [HA] Kw=[H+][OH-] ….② ⑤ 式, ⑥式を①式に代入して, Ka [A-]=[H+]-[OH-]=[H+]-[H+] grun [H+]=[HA] [A-] ・Ka= Kw 20 Kw [HA]=C-[A-]=C-[H+]+[* ⑥ ③ 式では, 酸HAのAに注目していま す。 平衡時はHA またはAの形でA が含まれています。 もともとAは1L あたり C〔mol] しかありません からわかるでしょう どうやっし ④式は、(正電荷の総量)=(負電荷の総量) HA → [H+] + [A-] - H+] + [OH-] MOV-10] (s) fax tu Kw C-[H+] + [H+Ⅰ Kw [H*]-TH*] よって, [H+] + K. [H+]2- (Kw+CK) [H+]-K.Kw=0 NO これを手計算で解くのは難しく, 水の電離によるH*の増加分を無視するなどの 近似が必要です。 答え [H+] + K. [H+]-(K.+ CK) [H+] K.Kw=0 ・Ka なぜ To

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