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English Senior High

全て教えて欲しいです

入試問題で 復習 & 力試し 5 1 ( )内に入る最も適切な語句を ① ~ ④ から選びなさい。 (1) It ( ) me a few minutes to realize that his email was a kind of joke. 1 consumed 2 lasted 3 spent (2) He seemed to be unfriendly, but I've ( 1 become 2 come (3) Please ( 1 allow ) me have a look at the picture. 2 force (4) Our school allows students ( 1 use 2 to use 4 took ) to realize that he is kind at heart. 3 imagined (6) We should have the patient ( ) by a doctor. 1 examine 2 examined (8) I like it when I can feel the rain ( 1 ran 2 runs 3 let smartphones after all the classes end. 3 to using 3 to examine Tooh Word Gift viksva (7) The waiting room was so noisy that I didn't hear my name ( call 2 calls 3 called (9) Many residents saw the car ( be stopping (10) ( (5) The light in the stairway was broken for months. It took way too long to get ( 1 someone 2 someone to (3) someone who ) in the middle of the street. 2 been stopping 3 to stop ) down my cheeks. E3 running () showed up for the politician's speech. Little person 2 Little of people (12) A good education will ( 1 enable ). ) you to have your own view of the world. 3 make 2 let LESSON 13~15 (13) A face shield might ( ) you from getting infected with viruses. 3 lead 1 bring SHONEntie sidin (2) cause (14) You are not ( ) to talk loudly in the library.JEY @better (3) capable 4 suggested 4 permit 4 into using 3 Few of person 4 gets (11) Listening to late-night radio programs (on) them relax after a long day. 1 kept 2 took 3 helps 4 to run (関西学院大) 4 someone will 4 stop (同志社女子大) (同志社女子大) 4 to be called 4 to be examined 4 take fix it. (慶應義塾大) (東京歯科大) 4 Few people (関西学院大) 4 supposed ayod) (杏林大) (群馬大) (獨協大) (芝浦工業大) (神奈川大) (宮城学院女子大) 3 (1) (日本大) gits be found ohsnt fid 4 prevent bue funds LadW ( 長崎県立大) (2) (3 (4

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Mathematics Senior High

AB,ACが平面上で一次独立とはどういうことでしょうか?また回答に書く必要がありますか?

F. wi 10 4点A(1,2,3),B(4,3,-1),C(3,4,0), D (2,5,z)が同一平面 2 上にあるような定数の値を求めよ. (考え方) 解答 GO ・3点A B C を通る平面上にDがあると考える. ・4点が同一平面上にあることより, D (d)はA (a), B(b), C(c) を用いて表すことが このとき, AD は ABとAC を用いて表すことができる. できることを利用してもよい。 AB=(3, 1, -4), AC=(2,2,-3), AD=(1,3,²-3) 点Dは3点A, B, C を通る平面上の点で, AB, AC が 平面上で1次独立なので、必要 とおける. AD=sAB+tAC (s,tは実数) 138A Focus したがって, HOLOG んが存在しない。 (1,3z-3)=(3,1, -4)+t(2,2,-3) つまり, A,B,Cは 一直線上にはない. 成分を比較する. 3s+2t=1 s+2t=3 -4s-3t=z-3 これを解くと s=-1, t=2, z=1+0=1-2-1 よって, 求める値は, z=1 058 050.0% 0510 VE 108 10 LERO DHAA & (別解) A (d),B(),C(c), D (d) とすると, 4点は同一 平面上の点より, #d=sa+to+ucose 533831138 (0-8) 1-nty 0≤ (s+t+u=1, s, t, u 0 とおける. GIF With te (2, 5, z)=s(1, 2, 3)+t(4, 3, -1) +u(3, 4, したがって (5-5)+(5-8) |s+4t+3u=2 2s+3t+4u=5 3s-t=z |s+t+u=1 **** これを解くと200 AB ¥0 かつ AC ¥0 で、 ABA となる 152. OB+GES 93 AS 24 0) SOR OE-551 4点を位置ベクトル で考える. (1) 001-1153 000 He 成分を比較する. +20 s=0,t=-1,u=2,z=1 (1) +8Op+AD よって、求める値は,z=1 03 s+t+u=1 を忘れ 0220分ずに40 A(d), B (b),C(c) のとき,P(n) が平面ABC 上にある ⇔ p=sa+to+uc (s+t+u=1) BRE 平面上に点P(1,y, 0)

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