Grade

Type of questions

TOEIC・English Undergraduate

【至急】この穴埋め問題の答えを教えて欲しいです。

Progress test (Part 1) Drag the words into the correct spaces. some of few 1/2 some a few enough neither lots of both little every each no information about attractions in the city. There are Coming to London for a weekend? Here's interesting places to visit - you won't have time to see them all. Firstly, visit to London would be complete without seeing Big Ben. The clock at the Houses of Parliament has become a symbol of London, but few✔ tourists know that Big Ben is actually the name of the bell, not day, so arrive early. the clock or the clock tower. On the opposite side of the river is the London Eye, the world's biggest observation wheel. holding 25 people, but there are still queues nearly There are 32 sections, If you'd like somewhere scientific, you could go to the Natural History Museum or the Science Museum. Entry to of these appeal to you, you may prefer Madame Tussaud's, the museum where is free. Or, if you can meet the world's most famous people made of wax. You could meet the Queen of England there, or you could hope to see her at Buckingham Palace, her London home, just the most valuable jewels in the world. stops away on the London Underground 'Tube' train. If you want to see more royal palaces, try the Tower of London, where you can see the Crown Jewels, If that isn't for one trip, why not go to Shakespeare's Globe Theatre, a reconstruction of the 1599 theatre extra money, you can even see a play there. where his plays were performed. If you have a

Waiting for Answers Answers: 0
Mathematics Senior High

この問題の(1)と(2)の回答の赤いところからなぜその式になるのかが分かりません。降べきの順は分かりますが、まとめ方が意味不明です😵‍💫😵‍💫 1問でもいいので、丁寧に解説していただけると助かります!!

次の式を因数分解せよ。 (1) a(b+c)²+b(c+a)²+c(a+b)²-4abc (2) x(y²-2³)+y(2²-x²)+z(x² - y²) CHART & SOLUTION 対称式・交代式の因数分解 1つの文字について降べきの順に整理する どの文字についても次数は同じ。 どれか1つの文字に着目して整理する。 (1) a²+a+● (2) x2+x+ 解答 (1) a(b+c)²+b(c+a)²+c(a+b)²-4abc&& =(b+c)a²+{(b+c)2+2bc+2bc-4bc}a+bc2+b'c =a(b+c)2+b(c2+2ca+α²)+c(a²+2ab+b2)-4abc1 =(b+c)(a+b)(a+c) =(a+b)(b+c)(c+α) Sans@sto ‚a+ð ‚ð+o 〔(2) 鹿児島経大 ] ●a²+a+ =(b+c)a²+(b+c)a+bc(b+c) 04648 (b+c)が共通因数。 =(b+c){a²+(b+c)a+bc} caについて降べきの順に整 和 : a + b→b+c→c+a 差:a-b→ b-c→c-a 積 : ab→bc→ca 基本 14,15 15-016-5)= た い ←これを答えとしてもよい。 輪環の順に整理。 CFR (2) x(y²-2²)+y(22-x2)+2(x²-y2) othis (ds) +1d理する。 (- =(-y+z)x2+(y²-22)x+yz²-y'z =-(y-z)x2+(y+z)(y-z)x-yz xについて降べきの順に整 (y-z) =-(y-2)(x²-(y+z)x+yz} KOST & =-(y-z)(x-y)(x-2). これを答えとしてもよい。 =(x-y) (y-z) (z-x) -=d+"p-dp輪環の順に整理。 ●x²+x++ (y-z) が共通因数。 INFORMATION 3つの文字についての式は,なるべく輪環の順に書くようにすると 式が見やすく、書き落としや間違いを防ぐことができる。 8x TOG'S a. 1章 (6) D 2 因数分解

Unresolved Answers: 1