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English Senior High

答えが公開されていないので、わかる方に答え合わせお願いしたいです😭🙇‍♀️

IV. (1) から (5) の各問いにおいて, 1.~6. の語句を並べ替えて空所を補い, 最も適当な英文 を完成させなさい。 解答は解答用紙2枚目 (記述式) の所定の解答欄に, (A)と (B)に入る語句の番号を記入すること。 (1) I like English because I feel like a different person when I am speaking it. Although it is difficult to speak well, I enjoy the challenge. Someday I hope ( ) (A) ( ) ( ) (B) ( ) in English. 1. even dream 5. the level 1. young people 2. acquire 5. provide (2) Volunteering is a good thing because it teaches young adults valuable lessons about life. For one, it teaches them that charity is an investment. By helping others you also help yourself. Volunteering can also ( ) ( A ) ( ) ( ) ( B ) ) practical experience. 1. health 5. to 2. where 6. I can. 1. lacking 5. found of what roles physical activity, exercise and nutrition play. neither prevent nor manage disease. 6. an opportunity (3) There are at least four kinds of education people should get when they are young: physical education, moral education, intellectual education and nutrition education. Those ( ) (A) ( ) ( ) ( B ) ( ) have an understanding Without them we can Q wear 5. we 3. reach 2. in 6. interested 3. with 2. and 6. more (4) E-mail and other SNS applications are now the primary means of communication in much of the world. While this is certainly one form of socialization, it seems to be replacing social interaction in person. As a result, more ( ) ( A ) ( ) ( ) ( B ) ( ) in the social skills and values that are essential to their integration into a group or community. 2 clothes 6. to 4. to 3. need 4. to 3. are (5) Presumably fashion reflects our personalities. The ( ) ( A ) ( :) ( ^_-) (B) ( ) who and what we are. Many people wear clothes to try and fit in, some to impress others, and some just wear the clothes they own. Your clothing is a reflection of who you are one way or another. 3. like 4. mental or physical 4. people 4. show Basic Elements for Communication (t, 2019 4), 7, 35, 59, 71, 87 ( 改変)

Resolved Answers: 2
Chemistry Senior High

⑷でなぜ1/5や4/5をかけないといけないんですか?

as (1) RE DOS 計算式 られるが、 量を一定に 式を立て 71 (1) ヘンリーの法則 (2) 酸素:32mL, 窒素:16mL (3) 酸素:窒素=1:2 (4) 酸素:窒素=4:7 (5) 小さくなる (2) ヘンリーの法則とボイルの法則により、水に溶ける酸素と窒素の体 積(それぞれの分圧での体積) は,圧力によらず一定である。よって, 溶けている酸素と窒素の体積は,1.013×10Paのときと変わらず, それぞれ32mLと16mLである。 (3) 物質量 〔mol]= 標準状態での体積 [mL] 22400 mL/mol で水1Lに溶ける酸素と窒素の物質量は, それぞれ 32 AMBIRAFFAX (0₂) 22400 16 22400 mol, F TE mol。酸素と窒素の分圧はそれぞれ1.013×10×Pa, (Hal 4 (SI) 1.013 × 105 × Pa であるから, ヘンリーの法則より,溶解した気体 5 7710 の物質量の比は, (a) 0.8-001x 20.8 32 22400 -mol x- 1 1.013×10³Pa×- 1.013×105 Pa 1 25 O2 の物質量 より,20℃, 1.013×10Pa (d) 201 013980. 4 1.013×10 Pax- 5 16 dommen. ・molx. 22400 ・mol× 28g/mol× 1 5 1.013×105 Pa N2 の物質量 =1:2 0.25 (4) 質量 〔g〕=モル質量 [g/mol]×物質量 〔mol] であるから, 溶解した 気体の質量の比は, [][][][\lom] 32g/mol× 32 22400 O2 の質量 (代) OH中 1.IX lom\g £8 21.501-20201 Tom 3.1 = 4:7 (5) 一般に,気体の溶解度は,温度が低くなるほど大きくなる。これは, 温度が上がると熱運動が激しくなり, 気体分子が溶媒分子との分子 間力を振り切って,外へ飛び出しやすくなるからである。DIXCES 02: Nz 1:4 Og0.S HOS () 1 比の値を求めるので, 1つ1つの具体的な数値 を計算せずに,約分する 1mol比Holm とよい。 4 22400 5 N2 の質量 56ad01408.$ £180.ES () {\om の MF 3673 (om 01.0 Tom 020.0 (loa) O

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