-
8. The temperature, 0ยฐC, of a cup of tea / minutes after it was placed on a table in a room,
is modelled by the equation
0 = 18 +65e s
Find, according to the n. el,
(a) the temperature of the cup ..
18โฐ โ
(1)
(b) the value of 1, to one decimal place, when the temperature of the cup of tea was 35 ยฐC.
35 = 18+ 65ฤ 7/8
-t/8
(3)
โ19=65โฌ
7/65
lu (17/4)= -4/8
(c) Explain why, according to this model, the temperature of the cup of tea could not fall
to 15 ยฐC.
HA
(0,94)
720
N = A + Re
en it was placed on the taki
(8,50)
1>0
ฮผ= A + Be 8
04-1
Figure 2
The temperature, ฮผ ยฐC, of a second cup of tea t minutes after it was placed on a table in a
different room, is modelled by the equation
Laverage
the room temp
0
-18
where A and B are constants.
Figure 2 shows a sketch of u against / with two data points that lie on the curve.
The line 1, also shown on Figure 2, is the asymptote to the curve.
Using the equation of this model and the information given in Figure 2
(find an equation for the asymptote /.
-trg
t>0
is 24ยฐC
04 142
(1)
4:10.7ยฒ
DO NOT WRITER
โฌ