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English Senior High

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UNIT 7 Reading Reading 33点 10点 Grammar /32点 /15 Information Listening Writing /10 TOTAL 100点 全文 音声 なまけ者のトムが望んだ仕事とは何でしょう。 Tom was a very lazy man*. He didn't like hard work. But he needed a job. One day, (his/Tom / a job / asked / uncle / him / find / to ). "What kind of job?" asked the uncle. Tom answered, "I don't want to work. I want meat for lunch every day. I just want to walk around and take naps*. And I want 100 dollars a day." "( )" the uncle sighed*. 2 One day, Tom got a call from his uncle. "Tom, I found the perfect job for you. A tiger at the zoo died recently. They need a new tiger. You can be the tiger. You'll wear a tiger's skin and walk around, eat meat, and sleep in the cage* like a real tiger." "( 3 )" said Tom. "I'll start tomorrow!" 5 3 The next day, Tom was in the cage in tiger's fur. He just walked around, ate meat, 10 and took a nap. Tom was happy. 44 Suddenly, he heard an announcement*. "We'll soon have a special show. It's a fight between a lion and a tiger! Enjoy this exciting show." "( )" He looked around his cage. Then another cage was carried next to his. A fierce-looking* lion was in it. "I'll be killed!" he cried. The doors of both cages were opened. Tom jumped back. "( 6 )" 15 The big lion slowly walked toward him, roared*, and opened its mouth. "Stop! I'm not a tiger! I'm a man!" 5 "Shhh!" Tom heard a small voice from the lion. "( Ⓒ )” (252 words)

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Chemistry Senior High

(1)なぜ、ag➕をyとしてcl -を0.1+yとしておけるのですか? (2)yは(1)のXより小さいのでってなんで小さいと分かって、0.1➕y(近似)0.1とわかるのでしょうか? また、赤で囲ったyってどの数字を表しているのですか?

塩化銀 AgClの溶解度積 Ksp=[Ag+][Cl-]=1×10-'" [(mol/L)] とす ると、 数字1桁で求めよ。 ただし, 溶解による体積変化は考えなくてよい。 次の (1), (2) に対する塩化銀の溶解度 (単位はmol/Lとする) を有効 (1) 水 (2) 0.1mol/Lの希塩酸(電離度は1とする) (1) 溶解度をx [mol/L], すなわち1Lあたり x [mol] の AgCIが溶解した とします。LO 溶解平衡時の濃度は, [[Ag+] = xm] [Cl-]=x なので, Ksp=[Ag+] [Cl-]=1×10-10 [(mol/L)²〕 に代入すると, xxx=1×10−10 [(mol/L)²2] よって, x=1×105 [mol/L] (2) 溶解度をy〔mol/L〕,すなわち1Lあたりy [mol] の AgCl が溶解した とします。 希塩酸中では[Cl-]=0.1 [mol/L] であることを考慮すると,溶解平衡時 の濃度は, [[Ag+]=y/ [Cl-]=0.1+ ・I+AM なので, Ksp=[Ag+][Cl-]=1×10-10 〔(mol/L)〕に代入すると, [2H] yx(0.1+y)=1×10-10 [(mol/L)*] 12.H] 共通イオン効果を考えると、はい)のより小さいので、 Q1+y≒0.1 と近似してかまいません。 そこで, yx(0.1+y)=v0.1=1×10-y =< 1/1/1417213260327 よって, y=1×10 [mol/L] 答え (1) 1×10mol/L なんひろなる [ all bolala (2) 1×10mol/L 260 A 319

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