Grade

Type of questions

English Senior High

本文2行目のplacing って何を意味しているのでしょうか? 教えていただきたいです!

次の英文 [A][B] [C] の内容に関して (27) から (38) までの質問に対して最も 3 適切なもの、または文を完成させるのに最適切なものを1.2.3.4の中から~ C [A] From: Noel Lander <noel@coffeeshopsupplies.com> <thedaydreamcoffeeshop@goodmail.com> To: Gary Stein Date: June 5 Subject: Your order Dear Mr. Stein, Thank you for placing an order by telephone with Jenna Marks of our sales department this morning. The order was for 500 medium-sized black paper cups with your café's name and logo printed on them. According to Jenna's notes on the order, you need these cups to be delivered to you by Saturday. I am sorry to say that we do not have any medium-sized black coffee cups at this time. What is more, the machine that makes our coffee cups is currently not working. The part that is broken was sent for repair the other day, but it will not be returned to our factory until Friday. Because of this, I am writing to you to suggest some alternatives. If you really need black cups, then we have them in small and large sizes. However, I guess that size is more important than color for you. We have medium-sized coffee cups in white, and we could print your logo on these instead. We also have medium-sized cups in brown. We are really sorry about this problem. Please let us know which of these options is best, and we'll send you an additional 50 cups for free. Our delivery company says we will need to send the order by Wednesday so that it arrives by Saturday. Please let me know your decision as soon as you can. Sincerely, Noel Lander Customer Support Coffee Shop Supplies

Solved Answers: 1
Chemistry Senior High

(4)の問題の解き方が分からないのと、解答に書いてある変化量の求め方がわからないです💦教えて頂きたいです!

例題16 化学反応の量的な関係 84, 85 マグネシウム 4.8g を燃焼させると, 酸化マグネシウムが生じる。0=16,Mg=24 とする。 (1) マグネシウムの燃焼を化学反応式で表せ。 マグネシウム 4.8gを完全に燃焼させるのに必要な酸素は何mol か。 (2)で生じた酸化マグネシウムは何gか。 マグネシウム 4.8gと酸素2.4gの反応で生じる酸化マグネシウムは何gか。 指針 反応量・生成量を求める場合は,化学反応式を書き,その係数を用いる。 反応式の係数の比=分子(粒子) の数の比=物質量の比=気体の体積の比(同温・同圧) 解答 (1) 2Mg+O2 →2MgO 4.8 g (2) Mg 4.8 g l 24g/mol は1mol とわかるので, 40g/mol×0.20mol = 8.0g答 MgOのモル質量 0.20 mol× 1/1/201 =0.10mol 答 (3) 化学反応式の係数より, 反応する Mg と生成する MgO の物質量が等しいとわかる。 mgD0.10× 4.8 g 24g/mol (反応前) (変化量) ( 反応後) = 0.20mol。化学反応式の係数より, Mg 2molの燃焼に必要な02 Loo.comal mg0=0.201 0.075 mol -0.075 mol 0 mol 初見里 (4) Mg は = 0.20mol, O2 は -=0.075 mol. (2) より, Mg4.8gの燃焼に必要なO2 は 0.10mol なので, Mg が過剰である。 そのため、 02 0.075 mol がすべて反応し, MgO 0.15mol が生じ, Mg が 0.05mol余る。 2 Mg + O2 2 MgO 0.20 mol -0.15 mol 0.05 mol Mg が余る。 生じた MgO 0.15 mol の質量は, → 12とられる 解説動画 2.4g 32g/mol 半分 40g/mol×0.15mol=6.0g 答 0mol +0.15 mol 0.15 mol om 18

Solved Answers: 1