Sn=n[2a1+(n-1)d]÷2
335=10[2a1+9×3]÷2
335=5[2a1+27]
65=2a1+27
a1=20
更正
倒數第二式是67=2a1+27
謝謝
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Sn=n[2a1+(n-1)d]÷2
335=10[2a1+9×3]÷2
335=5[2a1+27]
65=2a1+27
a1=20
更正
倒數第二式是67=2a1+27
謝謝
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