✨ Best Answer ✨
(1)
(与式)=3+4√3+4-(6-2√6+1)
=7+4√3-7+2√6
=4√3+2√6
(2)
x²+y²=(x+y)²-2xy
x+y=√5+√2+√5-√2=2√5
xy=(√5+√2)(√5-√2)=3
(与式)=(2√5)²-2×3
=20-6=14
両方解説お願いします
✨ Best Answer ✨
(1)
(与式)=3+4√3+4-(6-2√6+1)
=7+4√3-7+2√6
=4√3+2√6
(2)
x²+y²=(x+y)²-2xy
x+y=√5+√2+√5-√2=2√5
xy=(√5+√2)(√5-√2)=3
(与式)=(2√5)²-2×3
=20-6=14
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