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(x-1)をAとする
y(x-1)-3(x-1)=yA-3A
=A(-3+y)
=(x-1)(-3+y)
だと思います。
ありがとうございます🙇🏻♀️🙇🏻♀️
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y(x-1)-3(x-1)
↑これはxy-y-3x+3を変えた式です。