What can I do?
Study Talk
Q&A
Notebooks
subjects
Tutoring Schools
Sign up
Sign in
My Account
Already have an account?
Forgot password?
Sign in
Clearnote
Q&A
Junior High
Science
求解
Science
Junior High
over 4 yearsago
Ty
求解
請閱讀下列敘述後,回答 10~12題 右圖為一可旋轉的平面鏡,可依需要將固定光源反射至想要 的位置,已知目前光源射入的光和平面鏡夾 55 度。 55 ( 6 ) 10. 入射角為多少度?o-SS=S (A) 35 度 (B) 55 度 (C) 90 度 (D) 180度 ( D )1. 若入射角度維持不變,將平面鏡逆時針旋轉10度,則入射光與反射光的夾角為 多少度? (A) 25 度 (B) 35 度 (C) 50度 (D) 70 度 ( 012 承第11題,新的反射光與舊的反射光比較是以個方向旋轉,旋轉度數為何? (A) 逆時針,旋轉度數為10度 (B)逆時針,旋轉度數為20度 (C)順時針,旋轉度數為10度(D)順時針,旋轉度數為20度
八上理化4-2:光的反射
Answers
No answer yet
Login to post answer.
Login and Answer Question
Create New Account
Were you able to resolve your confusion?
Yes, all good!
Not really
Users viewing this question
are also looking at these questions 😉
Science
Junior High
over 4 years
求解