✨ Best Answer ✨
aの二乗をa＾とします
(b＋c)(a＾＋(b＋c)a＋bc)＋bca
(b＋c)a＾＋((b＋c)＾＋bc)a＋(b＋c)bc
＝((b＋c)a＋bc)(a＋(b＋c))
＝(ab＋bc＋ac)(a＋b＋c)
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✨ Best Answer ✨
aの二乗をa＾とします
(b＋c)(a＾＋(b＋c)a＋bc)＋bca
(b＋c)a＾＋((b＋c)＾＋bc)a＋(b＋c)bc
＝((b＋c)a＋bc)(a＋(b＋c))
＝(ab＋bc＋ac)(a＋b＋c)
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are also looking at these questions 😉
