Mathematics
Junior High
Resolved
違うところありますか?教えて欲しいです
=3√√2+6
問題1 次の計算をしなさい。
(1) √2 (√3+√5)
56
+ √TO
a XI
(3) (√12+√6)÷√3
√3
√3 3
=√4 + √2
2
OI
av + ave
01
I
I
=5√6-10
(2) √3(√6-√2
√3x2
= 3√√2 - №b
(4) (√2 +√3)(√6 − 2)
L3x4=257
EV 29x²
21-2√2 + √18 +2√3
2√3 - 2√2 + 3√2-2√√3
1
1
1
I
G
1
I
I
I
I
I
+ Eva (1)
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