Mathematics
Junior High
Resolved
DF:FC=5:2にどうやってなるのかがわかりません。
(3)x=CF
C
B
7
5
x
E
F
8
D
(3) △ADFは二等辺三角形なので, DF = DA=8 HA=x
DA: DC=AB:CB-5:7 DF:DC-5:70M-M8
2
2
DF:FC=5:2 となるので, x = DF × =8x-=
C, FA-FB
5
5
16
or|5
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