Mathematics & Statistics
Undergraduate
工程數學
微分方程式
③
y² + ³√y = x
y" + x³y² + (cos³x) y = X
©
(16
x
x+y=2014
Y
Əy²
1 x dy + (xy + cos x) dx = 0
1–2
✓ = y tanx
N
xx² = 34
u
y² + ²y + 5 = 0
at ²
xy +³7=2x
2X
(1+x²) dy - x²y dx = 0, y(1) = 4
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