Mathematics
Junior High
Resolved
この(4a^2-1)の-1って-1(2b+c)の-1ですか?
(5) 8a2b-2b+4a²c-c
= 8a2b+4a²c-2b-c=4a² (2b+c)-(2b+c)
= (2b+c) (4a²-1) = (2b+c) (2a+1) (2a-1)
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