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畢達哥拉斯定理
AE^2=AG^2+GE^2
BD^2=BG^2+GD^2
兩式相加
AE^2+BD^2
= AG^2+GE^2 +BG^2+GD^2
= AG^2+BG^2+GD^2+GE^2
畢達哥拉斯定理
= (AG^2+BG^2)+(GD^2+GE^2)
=AB^2+DE^2

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