仮定より
AB:AB=AC:AE･･･①
また、∠BAC=∠DAE
∠BAD=∠BAE-∠DAE
∠CAE=∠BAE-∠BAC
よって、∠BAD=∠CAE……②
①②より、二組の辺の比とその間の角がそれぞれ等しいので
△ABD∽△ACE
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仮定より
AB:AB=AC:AE･･･①
また、∠BAC=∠DAE
∠BAD=∠BAE-∠DAE
∠CAE=∠BAE-∠BAC
よって、∠BAD=∠CAE……②
①②より、二組の辺の比とその間の角がそれぞれ等しいので
△ABD∽△ACE
Users viewing this question
are also looking at these questions 😉
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