ΔADB∽ΔCEAが証明できてるなら
AEをxとおいて
6:x=(19-x): 10
60=19x-x^2
x^2-19x+60=0
(x-4)(x-15)=0
x=4,15
AD>AEより
AD=15 AE=4
どうでしょう?
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ΔADB∽ΔCEAが証明できてるなら
AEをxとおいて
6:x=(19-x): 10
60=19x-x^2
x^2-19x+60=0
(x-4)(x-15)=0
x=4,15
AD>AEより
AD=15 AE=4
どうでしょう?
Users viewing this question
are also looking at these questions 😉