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Answers
⑴ 最後 6/4√3の有理化が正しくできれば解けます
⑶ 余弦定理 b²=c²+a²-2ca・cosB より、
7²=8²+a²-2・8a・cos60°
a²-8・2・(1/2)a+64=49
a²-8a+15=0
(a-3)(a-5)=0
a=3, 5
Were you able to resolve your confusion?
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