✨ Best Answer ✨
電源装置の電圧をx[V]
図1の伝熱線Bに加わる電圧Vb1[V]
図1の伝熱線Cに加わる電圧Vc1[V]
図2の伝熱線Bに加わる電圧Vb2[V]
図2の伝熱線Bに加わる電圧Vc2[V]
Vc1=10x/(20+10)=1/3 × x
Vc2=x
Vc2/Vc1=3
答えは3倍です。
解説お願いします🙏
✨ Best Answer ✨
電源装置の電圧をx[V]
図1の伝熱線Bに加わる電圧Vb1[V]
図1の伝熱線Cに加わる電圧Vc1[V]
図2の伝熱線Bに加わる電圧Vb2[V]
図2の伝熱線Bに加わる電圧Vc2[V]
Vc1=10x/(20+10)=1/3 × x
Vc2=x
Vc2/Vc1=3
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