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例えば Ind⁽⁷⁾₃1 だと、
3⁰≡1 (mod 7)
なので
Ind⁽⁷⁾₃1＝0
となります
このように、各x=2,3,4,5,6に対して
3ⁿ≡x (mod 7)
を満たすnを一つずつ調べていけばいいです
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