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Physics Senior High

空欄の所分かりません

4月 30 日 J 版 15 (i)物体Aが時刻 30s に連度8.0m/s で原点を 通過後、x軸上を一定の加速度-2.0m/sで進む。 (a)=0~6,0s の運動をp-4 図に表せ。 (b)t=0~6.0s での移動距離(m), および =6,0s での変位 x[m] を求めよ。 (a) 時刻 での連度e は、 o=8,0m/s. a=-2,0m/" より ぃ=80-2.0f となる (下四)。 (m/s)t 等加速度直線運動の -t 図から変位を求める 日速度 D →岡回 -t 図の面構ー変位 x この部分の面 =6.0sのとき =8.0- 2.0×6,0=-4.0m/s + at ar 1. 8.0 この部分の面横= tu の=×8.0×4.0=16m 6.0 4.0 a) 0 D- (b) p-t 図の①+ ④の面積が移動距離!を、 の-のの面積が変位x を表すので O X= of + -4.0 の=合×4.0×2.0-4.0m 2変位の式 a<0 のとき を一定の加速度-2.0m/s" で運動する。時 刻=Os に原点を速度8.0m/s で通過した。 次の問いに答えよ。 物体Aがr軸上 1= 16+4.0= 20m *= 16-4.0= 12m 例題 時刻 t=D3.0s でのAの変位×[m] を求 めよ。 (3)物体Aが時刻 3Os に速度 12m/s で原点を通 過後、x軸上を一定の加速度-2.0m/s' で進む。 (a)t=0~8.0s のAの運動を ひt図に表せ。 解 a=-2,0m/s° =3.0s [m/s) =0s = 8.0m/s 変位 0 a= -2.0m/s。, v0=8.0m/s, t=3.0s よ り i (a) *= Dod + af=8.0×3.0+×(-2.0) ×3.0° = 15m (b) v-t 図を用いて=0~8.0s での移動距離1 [m),および t=8.0s での変位x(m] を求めよ。 変位と移動距離の違いに注意 変位xノ 移動距離 1)時刻t=2.0s でのAの変位x[m] を求めよ。 8.0X204×(-20x 2,0° 16+(-40)-ヤ (2m 1: (4)物体Aが時刻 %3D0S に速度8.0m/s で原点を通 過後、x軸上を一定の加速度-4.0m/s° で進む。 (a) t=0~5.0s のAの運動をひ-t 図に表せ。 p(m/s) ニ 時刻t=4.0s でのAの変位x [m]を求めよ。る 8.X40+台×(シx4,0° 0 ニ 32t(-10)= 16 16m 静刻t= 10.0s でのAの変位x[mを求めよ。 - 8,0X/a04x(-0)Xlo. (b) pt図を用いて t%3D0~5.0s での移動距離! およびt=5.0s での変位x(m] を求めよ。

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English Senior High

答えが合ってるか教えてくれると嬉しいです!

【1】 ~【8】各2点 【9】 各4点 英語演習 (2) No.1 [e] [8][11 o 【4】 次の英文の下線部の意味に最も近いものを選び、記号で答えなさい。 1. Bob made up his mind to propose to Dorothy. あ) prepared い) hoped う) decided え) began 2. Her dream to be a singer came true after all. あ) fortunately い) ( え う) lately え)totally eventually 3.I couldn't put up with the loud music firom the house next door.)( hear にの方 stand wan omoe ob vi い) da う) complain え) あ) increase へ 4. Please callon us whenever you want to.( あ あ)visit uode bainrow sigosg sedipy え) trust い)telephone う) tell 【5】 下線部と同じ用法のものをa~dから選び、記号で答えなさい。 (1) No one was to be seen in the village. (2) Aconcert is to be held at the stadium this weekend.の (3) Ifwe are to win the game, we must practice much harder. (4) You are to show the contents of your bag at the entrance. ( d (biw) a. The President is to arrive at the airport at three. b. You are to turn off your cell phone in the hospital. C. No treasure was to be found in the ruins. d. You must leave here right now if you are to get there in time. pre () 1oieolapzs ① Iegelli S Lsups D busotaog () 90don © IeTo 19q0 の )に入る適語を選び、 番号で答えなさい。 【6】( 1. One after ( 3/ の two )the swans flew away from the lake. 3 other 2 each の another 2. This PC won't start up. There must be something ( CL )with it. O hard 2 wrong 3 good 4) common J さ ま 景る人( 3. It' your (( ) towalk the dog today. 0 need 2 order 3 turn の place )i aroiniqo iedh evsg atnsburta o 9010 4. Finish packing quickly. 3) We have not time to ( 2 lose 3 keep ④ leave v w )m ggnia sotbeq bloods us O go 5. In Great Britain, () )police officers carry guns, but most of them do not. ol boool sids の few 2 any brpi (3) some の the ) he hurried, the shop was closed when he got there. O Despite )i iol sasd ssteas O Although ② Regardless of ③ In spite of 7." Is she going to get well soon?” “I( 1) )" 2 am afraid not の hope it want so の wish so

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Chemistry Senior High

読みましたが、全体的に理解出来ません。英語で理解出来なかったので多分、全文和訳しても理解出来ません。 なので、この写真に載っていることを分かりやすく教えていただきたいです🙇🏻‍♀️

Free energy changes determine if a reaction is endothermic or exothermic. Processes in nature are driven in two directions: toward least MAIN IDEA enthalpy and toward greatest entropy. When these two oppose each other, the dominant factor determines th direction of change. As a way to predict which factor will dominate fora given system, a function has been defined to relate the enthalpy and entropy factors at a given temperature tropy and constant pressure. This combined enthalpy-entropy function is callepd t free energy, G, of the system; it is also called Gibbs free energy. This function simultaneously assesses the tendencies for enthalpy and entropy to change. Natural processes proceed in the direction that lowersthefree energy of a system. Only the change in free energy can be measured. It can be defined in terms of changes in enthalpy and entropy. At a constant pressure and temperature, the free-energy change, AG, of a system is defined as the difference between the change in enthalpy, AH, and the product of the Kelvin temperature and the entropy change, which is defined as TAS. Free Energy Change AGO= AH°- TASO Note that this expression is for substances in their standard states. The product TAS and the quantities AG and AHhave the same umor usually kJ. The units of AS for use in this equation are usually N If AG<0, the reaction is spontaneous. AH and AS in the free-energy equation can have positive or negative values. This leads to four possible combinations of terms.

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