関係詞で自分のことについて文章をつくる問題です。例文を教えてください。よろしくお願いします🙇

Write about yourself or your friends/family. Use however in 1) and whenever in 2). 1) However 2)

13番の問題で答えが4になるのですがなぜ4になるのかと他の選択肢が違う理由を教えていただけると助かります よろしくお願いしますよう

(13) In the twentieth century engineers were excited about ( Dthat was accomplished they accomplished L1-1 ) by the computer industry.

教えてください🙇‍♀️

B()に入る最も適した複合関係詞を右から選んで書きなさい。 文頭に来る文字も小文字に この なっています。 (1点×6=6点) F 1. I am interested in ( ) you write. however 2. Come and see me ( ) it is convenient for you. whatever 3. You may invite ( ) wants to come. whenever 4. ( ) hard you try, you will never finish it in a week. wherever 5. ( says so, I don't believe it. res whoever 6. ( ) you call on Ben, you will find him reading a book.

対角線BDの求め方教えてください！🙇🏻‍♀️答えは√5です！

* 1 ~ と (2), (2) は答えのみを解答欄に記入せよ。 それ以外は、 途中経過を詳しく記入すること。答えのみは不正解とする ① A(-1, -2), B(2,0), C(3,3), D(x, y) の4点を頂点とする四角形ABCD が平行四辺形であるように,xyの値を定めよ。 また, そのときの対角線 BD の長さを求めよ。 【知※各3】

高校受験を控える弟のテストです。回答がなく困っています。どなたか回答してくれませんか？

BO (2)次は,かえで町で開催されるイベントのお知らせです。 Kaede Summer Festival We will have Kaede Summer Festival in Kaede Park in August. There will be more than 60 shops, and you can enjoy many events on stage. In the evening, you will see beautiful fireworks. Come and enjoy the summer! Schedule <Day 1> Saturday, August 10 From 9 a.m. to 9 p.m. 10:00 Yosakoi Dance 1:30 Music Performance by 6:00 Mr. William Teller Bon-Odori 7:00 Fireworks Show Information about Events Mr. William Teller will join our festival. He is a famous singer around the world. When he was younger, he lived in Kaede Town for one year. He decided to come back for Kaede Summer Festival this year. Come and enjoy his great music! <Day 2> Sunday, August 11 From 9 a.m. to 8 p.m. 000.00 00002 11:00 Dance Performance by children 3:00 Yosakoi Dance 6:00 Bon-Odori 7:00 Fireworks Show Kaede Yosakoi dance team will show their performance. They won a Yosakoi contest in Hokkaido last year. Their performance will be exciting. They have made their dance easy for the people of Kaede Town. You can dance with them! On the second day, children of the dance club at Kaede Elementary School will perform their dance. They practiced dancing hard for this festival. Enjoy their cool dance! will sď You can see the fireworks show from anywhere in the park. * Children under 13 years old can't enjoy the festival after 6 p.m. without a parent. (E) schedule anywhere どこでも W in evil won bis vti alueji ni rood asw.exp VT to adband pig box by var Joods moilimbi amox fox ral0Y+ rady (nam you of ved Imobre VIO 2008 in noble nibit won a toy tili da ni vil o bha alging so I -7-

執権と得宗は結局なにが違うのか教えてください

これがどうして成り立つのか分かりません。教えてください🙇

出題テーマと考え方 2つのmnの式の最大公約数 → 整数 α, b, c, q に対して,a=bg+cが成り 立つとき, ともの最大公約数はbとcの最大 a 公約数と等しい。 これを利用する。

(3)の正しい答え教えて欲しいです！！ よろしくお願いします

wa has seen in to Work in the laboratory can ③ deny that Carter has an ④ interest in conducting chemical experiments. を行う 知覚の後ろは原形 or doing ( 京都外国語大) (3) The tourists ① who talked to us in Asakusa said ② they were from Sweden. They asked us ③ what do you think of their country ④ while emphasizing how much they loved Swden 在する Japan. (南山大) (4) There are so I many types of weather ② of Japan: in Tokyo ③ alone, there are ④ a lot of different types

答えお願いします。

Emma: What has encouraged you to work as a stamp designer for over 30 years? Tamaki: Stamps introduce the culture, history and nature of each country. It's an honor of YOUT2 to be involved in the process of making such "small diplomats." I hope my designs are interesting and attractive. I'll keep making designs that people enjoy. Emma: Thank you so much. We're looking forward to your next stamps.

例27です。ピンクマーカーのとこがよく分かりません。

[リード C Let's Try! 第6章 熱とエネルギー 61 例題27 熱量の保存 ➡ 78, 79, 80 解説動画 熱量計の中へ140gの水を入れたとき,容器も水も一様に温度が27℃になった。 (1) 図1のように,この中へ47℃の水 40g を追加したところ、全体の 温度が 31℃になった。 容器の熱容量Cは何J/K か。 水の比熱を 4.2J/(g・K) とする。 (2)さらにこの中へ、図2のように,100℃に熱した 150g の金属球を 入れてかきまぜたところ,全体の温度が40℃になった。金属球の 比熱cは何J/(g・K) か。 150g 100°C 40g 140g 47°C 180g 31°C 27°C 図 1 図2 指針「高温物体が失った熱量=低温物体が得た熱量」すなわち、熱量の保存の式をつくる。 解答 (1) 熱量の保存によって 40×4.2×(47-31) =(140×4.2+C)×(31-27) これを解いて C=84J/K (2) 熱量の保存によって 150×c×(100-40) ={(140+40)×4.2+84}×(40-31) これを解いて c=0.84J/(g・K) [POINT 熱量の保存 高温物体が失う熱量=低温物体が得る熱量