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English Senior High

問3について質問です。 当方、全くいい案が浮かばなかったのですが、皆さんがこのような英作文に当たったらどう対処しますか❓ 具体例としてはニホンカワウソやツシマヤマネコ、トキ、コウノトリが挙げられるようですが私はどの生き物も英語で書けません。(/ω\*) ちなみに私はホ... Read More

次の英文を読み, 設問に答えなさい。 Jaguars had called the American Continents their home since the Ice Age when their ascendents crossed the Bering Land Bridge that once joined what is now Alaska and Russia. They lived in the central mountains of the southwestern United States for hundreds of years until they were almost driven to extinction in the mid- 20th century after hunters shot the last one in the 1960s. Currently, jaguars are found in 19 different countries. Several males have been observed in Arizona and New Mexico over the last 20 years, but breeding pairs have not been seen or reported north of Mexico. Natural reestablishment of them is also unlikely because of urbanization and the U.S.-Mexico border blocking jaguar migration routes. Now, after more than a 50-year absence, conservation scientists are suggesting the jaguar's return to their native environment in a study that outlines what the rewilding effort may look like. The authors of the new paper suggest a suitable area for jaguars spanning 2 million acres from central Arizona to New Mexico. The space would provide a big enough range for 90 to 150 jaguars, the researchers explained. They also argued that bringing jaguars back to the U.S. is crucial to species conservation as they are listed as near-threatened on the IUCN Red List, and reintroduction could also help restore native ecosystems, the Associated Press reports. "The jaguar lived in these mountains long before Americans did. If done

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Mathematics Senior High

1番の解説3、4行目が表しているのは 赤で書いているようなことですか? 中心間のキョリ=√8<3(最も近い実数)より、 3=1と2に分けることができて、 √5>2かつ√2>1だから、 2+1<√5+√2(中心間のキョリ<半径の和) √5>3かつ√2>1なので、√5-√2<... Read More

基礎問 68 第3章 図形と式 water 422円の交点を通る円 2円x2+y²-2.z+4y=0..... ①,_z'+y^+2x=1......② がある. 次の問いに答えよ. (1) ①, ② は異なる2点で交わることを示せ. (2) ①② の交点をP, Q とするとき, 2点P, Q と点 (10) を通 る円の方程式を求めよ. (3) 直線PQ の方程式と弦PQ の長さを求めよ. (1) 2円が異なる2点で交わる条件は 「半径の差<中心間の距離<半径の和」です。 (数学Ⅰ・A57) (2) 38 の考え方を用いると, 2点P, Q を通る円は (x2+y²-2x+4y)+k(x2+y2+2x-1)=0 精講 の形に表せます。 (3) 2点P,Qを通る直線も(2) と同様に I (x²+y²−2x+4y)+k(x²+y²+2x-1)=0&pa Jel と表せますが,直線を表すためには, ', y'の項が消えなければならないの で,k=-1 と決まります.また,円の弦の長さを求めるときは, 2点間の距 離の公式ではなく,点と直線の距離 (34)と三平方の定理を使います. 答 解 (1) ①より(x-1)²+(y+2)^=5 ② より (x+1)^2+y²=2 中心間の距離=√2+2°=√8 <3=2+1<√5 +√2 また, √5-√2<3-1=2<√8 .. 中心 (1,-2), 半径√5 中心 (1,0), 半径√2 ∴. 半径の差<中心間の距離<半径の和 よって, ①,②は異なる2点で交わる. (2) 2点P.Qを通

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