Grade

Subject

Type of questions

English Senior High

下の問題を教えてください。m(*_ _)m

各文の( 内の語のうち,より適当なほうを選びなさい. (1) The ground was covered with (falling, fallen) leaves. (2) He is a famous pianist (knowing, known) all over the world. (3) Ann looked (exciting, excited) about going to the opera. (4) Phil kept me (waiting, waited) for half an hour. (5) They watched the firefighter (climbing, climbed) the ladder. (6) (Leaving, Left) alone, the little boy began to cry. (7) I had my bag (carrying, carried) to my room. 2 日本文の意味に合うように( (1) 私たちは先週の土曜日東京に買い物に行った. We( ) ( (2) ネズミはネコを見ると全速力で逃げた. に適当な語を入れなさい . ) Tokyo last Saturday. ) a cat, the mouse ran away at full speed. (3) 私は顔が赤くなっていると感じた. I felt my face ( ) red. (4) リスクを考慮に入れると, その計画は延期するべきだ . ) the risk into consideration, we should put the plan off. (5) トニーは自分の名前が黒板に書かれているのを見つけた . Tony( ) his name ( (6) 彼女は部屋の外で立ったままだった. She( ) on the blackboard. ) ( very impressed. ) outside the room. 3 各組の文がほぼ同じ意味になるように( )に適当な語を入れなさい . (1) She took off her hat, and bowed to me. ) ( ) her hat, she bowed to me. (2) Since I didn't know what to do, I looked around. ) ( ) what to do, I looked around. (3) After I had finished my homework, I went to the movies. ) my homework, I went to the movies. 1 (1) (2) (3) (4) (5) (6) (7) (4) As it was Sunday, most shops were closed. ) ( ) Sunday, most shops were closed. (5) As I had not heard such a beautiful melody, I was very impressed. ( ) heard such a beautiful melody, I was (1 (2 (3

Solved Answers: 1
Mathematics Senior High

なぜ傾きが√3だったら角OAP=60°とわかるんですか?

123 放物線と円 5 放物線y=- 8 この円と放物線で囲まれる部分の面積を求めよ。 ただし, 円と放物線が共有点Pで接するとは, その点で同じ接線をもつこ とである. ( お茶の水女大) 点A(0, 2) を中心とする円が異なる2点で接するとき、 一般に、2曲線 y=f(x), y=g(x) 解法のプロセス が接するというのは、 “共有点Pを 島精講 もち,Pにおける接線が一致する” ことです. 共通接線がy軸と平行となる場合を除けば、 [f(a)=g(a) となる実数αが存在する [ƒ'(a)=g'(a) ことです. 本間では 放物線と円が点P で接する ⇒ 放物線上の点Pにおける接線がAを中 心とする円の接線でもある APLI [P は円上の点(APは円の半径) といいかえることができます. S=p^ 解答 放物線上の点P(t.ford) (10) における接線の傾きはであることから YA -t²-2 APHI⇔ t したがって,接点はP ( 13 3. Cos).p(-1/31/3号/5) P(-√3, 13, St -t=−1 半径 AP= √ ( 1/2 √ 3 ) ² + ( 15 - 2)² = = 放物線と円がPで接する ↓ 放物線の接線が円の接線 ↓ 円の中心がAなので APLI AP は円の半径 面積= 4 t = ± √√√3 8 5 この傾き=√3 より 求める部分の面積Sは,上図の斜線部分だから ∠OAP = 60° ..∠P'AP=120° s P" A 2 P扇形 APP (α=-1/3√3,B=1/12/3 とおくと)

Solved Answers: 2