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English Senior High

本文2段落目の最終文、well,why can't I?はなぜわたしにはできない?いやできるでしょ!みたいな意味でしょうか?? 〇なんで私には出来ないんだろう。 〇ヘミングウェイもできたんなら私にだってできるでしょ。 どっちなんだろうと思いました、、、 どなたか教えて下... Read More

48 B** You found the following story in a magazine. ol bon tote Hemingway and I Ryoko Yamanaka (Novelist) The author m. の Chicago Chicago 問1 Fukuoka Fukuoka の a S to be like him in the future, SoonI started to write short stories. 問2 The autho: 0 Florida O Fukuok After six years, I moved to Key West, Florida. I chose the cit.. because that was where Hemingway spent his last eight years. I majored in American literature at the university there. My future ambition was 9- linois 0 Tokyo still to be a novelist. Of course, gettinga degree in literature does not mean you can be a novelist. After graduation, I started to work in Tokyo as a journalist for an American newspaper company. Hemingway was a journalist, before he becamea novelist. He wrote about his experiences in Europe and became a best-selling author. I thought, “well, why can't I?" 問3 The at ABU For the next twenty years, I worked as ajournalist. It was a busy job. I could not afford time to write a novel. I almost gave up my childhood dream. Then, I wasin a car accident. On abed in hospital, I remembered 0 Cou 2 rea 3 wa Hemingway was heavily injured in the First World War and was sent back to America. He became a novelist after that . Fortunately, I could move my hands. I started to write novels again. At the age of 45, my first novel was published. So far, I have written five novels, all of which have been favorably accepted, luckily. I should never be a literary master like Hemingway, but at least, my ambition since childhood was fulfilled. Route A r park dos en

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Mathematics Senior High

赤線部が分かりません。 3枚目の写真のようになるのではないかと思ってしまいます。 分かる方いらっしゃったら教えて頂けると嬉しいです

(1) f(z)は ェ=0 で連続であるが, S'(0) は存在しないことを示せ, (2) g'(0)は存在するが, g'(z)は エ=0 で不連続であることを示せ。 専問 23 微分可能と連続 (エ=0) 0 (ェ=0) 0 9(z)= f(x)= r'sin I とする。 (エキ0) Isin I . (0キエ) (鳥税 連続性,微分可能性, いずれも定義 に立ち返って考えます。 (1) f(0)=0 ですから, エ=0 で連続であるこ 解法のプロセス エ=0 で連続(微分可能)を 精講 f(0)=0 だから とは 1 =0 lim f(h)=limhsin oi23limf(h)=0 h h→0 h→0 h→0 f(h) が成り立つことです. 問題は振動する sin の h lim が存在する \h→0 h を示す 扱い方ですが,sin-S1 を用いてはさみ打ち にします。f(0) が存在しないことを示すにも, 微分係数の定義にもとづいて, 三角関数の値の振 動に注目することになります。 (2) ほぼ(1)と同様です。 ただし, (1)の結果をう まく利用して簡潔な答案になるように心がけます。 解答 (1) f(0)=0 より 0<|f(h)-f(0)|=If(h)|=|hsin-<lh| はさみ打ち . 1f(h)-f(0)|→0 (h→0) : f(h)→ f(0) (h→0) ゆえに,f(z) は エ=0 で連続である.次に f(h)-f(0)-sin(hキ0) S1 h 2 において, limsin は振動して有限な値に収束 (n (2n+1)π =h h→0 とすると, しないから,f'(0) は存在しない。 sin-=(-1)" h

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