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English Senior High

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Akemi Hamano, a recruiting consultant at *Hays, says that, with the exception of blue-collar positions, companies are looking for a business level of Japanese ability sufficient for frequent back-and-forth communication and being able to make ( 1 ) together. David Price, client services director at *Robert Half, is more *succinct. "In most cases it's pretty simple - if your co-workers and/or clients can't or won't speak your language, then you must speak (and often read and type) ( 2 )," Price says. At the same time, whereas ( 3 ) for conversational level abilities are high, Alan Adkins, president of *The Refined Group, notes that there is more flexibility when it comes to reading and writing, due to an awareness that learning kanji is hard. The value placed on Japanese ability may not be only related to ease of ( 4 ) top communication. "Many companies also look at business level Japanese ability as a sign of ( 5 ) to Japan as well as solid work ethic as most Japanese people seem to understand how difficult their native language is,” says Anthony Blick, a senior consultant at *PowerUp Solutions. 注) Hays 会社の名前 Robert Half:会社の名前 succinct : 簡潔な The Refined Group : 企業グループの名前 PowerUp Solutions: 会社の名前 ( 1 ) 7. decisions X (2) 7. mine (3) 7. exceptions Y (4) 7. academic X (5) 7. command 7. illustrations 1. yours 1. expectations 1. business 1. commitment . quarrels 7. ours goog . experiences . daily . compassion pre prior 200 I. subscriptions I. theirs I. experiments I. professional I. competition

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Mathematics Senior High

⑵の問題で、なんで0<α<π/4となるんですか??

At Ant ( 例題 162 例題 思考プロセス 1164 三角関数の最大 最小 〔4〕… 合成の利用 (1) 関数 y = sin03 cos (0) の最大値と最小値, およびそ のときの0の値を求めよ。 537831=0ex+Wmia (1) (2)関数 y = 4sin0 +3cost (0≦a≦ サインとコサインを含む式 (1) y = sin0-√3cost 合成 ↓ « Re Action asin0+bcos0 は, rsin (0+α) の形に合成せよ 例題 163 0 ≤ 0 STA 0 - 2 sin (0-5) 3 サインのみの式 y = The 0- よって したがって π 2 π 0-3--== (1)y=sin0-√3cose π OSOS D - 50 - sze π より 2 π 3 3 3 B 0≤0 ≤ VII π ≦ (2) 合成すると,αを具体的に求められない。 nai →αのままにして, sinα, cosa の値から,αのおよその目安をつけておく。 π ≤ 1/2 kb より ≤ sin (0-3) 2 sin (0-5) π 2sin(0- 3 √3≤sin(0-3) ≤1 2 -√3=2sin (0) 2 π 3 y = 4sin0 +3cos=5sin (0+α) とおく。 3 ただし, αは cosa= 5 TT 10-10/1 sina = a ≤0+ a ≤ から 2013 sin (+α) ≦1 5 3 ≤ 5sin(0+ a) ≤ 5 £h, y l Don の最大値と最小値を求めよ。 17 π 2 すなわち 0 = のとき最大値2 5 6 S +0)nie S = 8800+aja S + 18 +α すなわち0=0 のとき 最小値-√3 図で考える gie)S-680-anie S - & ・① を満たす角。 ①より0<a<こであり、sina < sin (+α) である 4 Danies +1 T 3 O 40= 3 38Typ 100 2 2010 最大値 5,最小値3 2 O -1 10- +0m2 300 S P a 1x √3 2 = } -1| $3@1=1 (3) YA S>020 3 x R 〃 1 x 3 YA -1 0 [出] 4 AR sina sin (+α) ≦1 ■ 164 (1) 関数 y = sind-cost (0 ≦)の最大値と最小値,およびそのときの 練習 ma 4/1 x 5 0 の値を求めよ。 376 3 1 = 0800+Onia (1) (2) 関数y=5sin0 +12cos (0 ≦)の最大値と最小値を求めよ。 n311 問題164 3 章 1 加法定理 10 293

Resolved Answers: 1