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English Junior High

写真の問題より、(3 )に入る言葉の模範解答がbigger,largerだったのですが私はmoreとかきました。moreだとバツにたりますかね?

Tony: What are you going to make a presentation about? Riku I'm going to introduce my idea for a new park. Here is a graph showing "Roles which people want for parks." I think parks serve many important roles. I want to make a wonderful new park in my town in the future. Tony: Great! Riku What is the most important role for parks for you? Tony: Well, I think "A place for eating" is the most important. Riku: I think that is important too. But its percentage is the lowest in this graph. Roles which people want for parks A hub for the community A place for exercise and sports A place for children to play A place for relaxing A place for eating 0% 10% 20% 30% 40% Tony Interesting. In my country, I often enjoy eating lunch in a park. Riku: I think "A place for children to play" is the most important. Many other people also want that role. Tony Yes. Its percentage is a little lower than that of "A place for exercise and sports" and "A hub for the community." But it's higher than the percentage for the other roles. Riku Parks can play a lot of roles in a town. I'll try to make a park that serves important roles. There are many possible roles for a park in a town. I hope people find good roles for my park. Tony: Great! I think your presentation will be really interesting. I want to know more about parks and towns. hub +0 <要約文> Riku is going to introduce his idea. He and Tony look at a graph that shows some (1) which people want for parks. As for the (2) important role for parks, Riku thinks it is "A place for children to play," but Tony thinks it is "A place for eating." According to the graph, the percentage of Riku's opinion is (③) than Tony's. Riku hopes to make a park that plays important roles.

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Mathematics Senior High

ここの2番の書いてある意味がわからないので,一つ一つ教えて欲しいです。

重要 xy 例題 21 内積を利用したux+vy の最大・最小問題 00000 平面上に点A(2,3)をとり、更に単位円x2+y2=1上に点P(x, y) をと る。また、原点を0とする。 2つのベクトル OA, OP のなす角を0とすると き内積 OA・OPを0のみで表せ。 (2) 実数x, y が条件 x +y2=1 を満たすとき, 2x+3yの最大値、最小値を求め 指針 [愛知教育大 〕 (1)Pは原点Oを中心とする半径1の円 (単位円) 上の点であるから |OP|=1 (2) (1)は(2)のヒント A(2,3),P(x, y) に注目すると 2 x +3y = OA・OP かくれた条件-1≦cos 0≦1 を利用して, OA・OPの最大・最小を考える。 基本11 1 章 3 ベクトルの内積 解答 OA・OP=|OA||OP|cose =√13cose (2)x2+y=1 を満たす x,y に | (1) |OA| =√22+32 = √13, |OP|=1から YA A(2,3) 内積の定義に従って計算。 対し, OP = (x,y) DA = (2,3) として2つのベ クトル OA, OP のなす角を とすると, (1) から -10 1 x 2x+3y=OA・OP=√13cos 200 20°180°より, -1≦cos≦1であるから, 2x+3y の 0=0°のとき最大, 最大値は 13 最小値は13 0=180°のとき最小。 |-|OA||OP|SOA・OP k 別解 1. 2x+3y=kとおくと 2 y= -x 3 3 Fonie |OA||OP| これをx2+y2=1 に代入し, 整理すると 13x24kx+k2-9=0 ...... ① から求めてもよい (p.612 重要例題 19 (1) 参照)。 20 xは実数であるから, xの2次方程式 ① の判別式をD xは実数であるから,x とすると D≧0 D =(-2k-13(k-9)=-9(k-13) であるから k2≦13 よって√13≦k≦√13 別解2. (x,y)= (cos 0, sin01) と表されるから 2次方程式が実数解を もつ 実数解⇔ D≧ (数学Ⅰ)である 三角関数の合成 ( 数学II) 2x+3y=2cos01+3sinA=√22+32sin(01+α)=√13sin(01+α) 3 2 ただし COS α= √13 sina= √13 1main (+α) ≦1であるから -√13≦2x+3y≦√130°≦0,<360° 2 =2を満たすとき, ax + by

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