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English Senior High

214の回答がDになる理由がわかりません。 製品の安定需要という内容はどこから読み取れるのか教えてください

Samuels LAX, announced on Movey that it will spend $1 billion to build nylon production and processing facilities in Singapore to serve the Asia Pacific region. Construction of the 45,000-square- meter plant will take two years. When the factory is complete, it will employ over 500 workers and have an estimated annual production of 60,000 tons of nylon and nylon components. According to company spokesperson Michael Tan, the plant will be equipped with the same advanced technology used in Samuels plants in India and Canada, enabling the company to price its nylon competitively. The nylon products will be sold to 213. What is the purpose of the article? (A) To publicize new merchandise (B) To discuss a company's plans for expansion (C) To explain a problem with a product (D) To describe the layout of a factory 4 Part Part applications. companies throughout the region for use in various industrial textile The Asia Pacific market for nylon has remained strong over the last decade, with the majority of purchases coming from the automobile manufacturers, Samuels is hoping that the efficient production from the new factory will position it to become a leader in the market. It will face stiff competition from Haring Corporation, the current leader, and from several other large chemical companies that ship nylon products into the area from Europe and Africa. 214. According to the article, why did Samuels Ltd., choose to target the Asia Pacific market? (A) It can ship in products from its existing plants. (B) There is no competition in the region. (C) Raw materials are available locally. (D) There is a steady demand for the product.

Solved Answers: 1
Mathematics Senior High

この問題で、解答ではAH=sAB+tACで解いてますが、✱の部分のlOA+mOB+nOCの方法で解いてくれませんか この方法でやると何故か全部0になるんですけど

基本例題69 平面に下ろした垂線 (1) 17 00000 空間において, 3点A(5, 0, 1),B(4, 2, 0), C(0, 1,5) を頂点とする三角形 ABCがある。 原点O(0, 0, 0) から平面ABCに垂線を下ろし, 平面ABCとの 交点をHとするとき, Hの座標を求めよ。 基本 67 指針 点Oから平面ABCに下ろした垂線の足に対して, 大点は平面ABC上にあり, ととらえて考える。 10×120×HAO. 直線 OH は平面ABCに垂直であるから, 直線 OH は平面 ABC 上のすべての直線と垂直である。 よって ゆえに よっては OH⊥AB, OH LAC ゆえに OH・AB=0, OH・AC=0 解答 AB=(−1, 2, −1), AČ=(−5, 1, 4)×0+0×$+(1−)×(1 点Hは平面ABC上にあるから, AH=sAB+tAC (s, t は実 数) (*) とおける。 ゆえに OH OA+AH 右上の =OA+sAB+tAC =(5,0,1)+s(-1, 2, -1)+t(-5, 1,4) ① OHLAB, OHLAČ OH」 (平面ABC) であるから OH⊥AB から OH・AB=0 よって ゆえに 2s+t=2 OHACから =(5-s-5t, 2s+t, 1-s+4t) -(5-s-5t)+2(2s+t)−(1¬s+4t)=0 s+14t=7 - PI=. ...... OH・AC=0 h=-5(5-s-5t)+1・(2s+t)+4(1-s+4t)=0 ② ③ を解いて ...... かつ,直線OHは平面ABCに垂直である S= 7 9 よって, ① から KOOTUSTE t= 9 H(2, 2, 2) ...... 4 9 mx C (8 0 I- ZA JUAN C BD HO 重要 71 CA H OH =LOA+mOB+nOC, け+m+n=1 として考えても よい。 B (HAL)=(A)+(8A)+(ADA) すものであり、 y TOATE CA 8 8 90/1 0 2) B(2 1 (0) CU C Hote FORSERORTE 3

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