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Science Junior High

この問題の(4)教えてください

5 6 〔分] (1) 流れる向きが周期的に変化している電流を, 交流という。 家庭のコンセントに供給されている電流は, 交流である。 な お、乾電池の電流のように、一定の向きに流れる電流は,直 流という。 (2) 消費電力が1200 W の状態で使用したときは12A, 消費 電力が600W の状態で使用したときは6Aの電流が流れる。 (3) 600 〔W〕 x 30[s] = 18000[J] (1) 同じ大きさの電圧を加えたとき, 抵抗が小さいほど流れ る電流は大きくなり, 電力も大きくなる。したがって, 抵抗 が小さい電熱線Aのほうが, 電熱線Bよりも電流は多く流 れ 電力は大きい (2) 電熱線Aに流れる電流は, 6 (V) 2[Ω] は, 3 [A] × 6 [V] = 18〔W〕 となる。 これより, 5分間電流 を流したときの電熱線の発熱量は, 18 〔W〕 × 5 × 60 [s] = 5400〔J〕 (3) 電熱線Aに加える電圧を3Vにしたときに流れる電流の 大きさは1.5A なので、電力は1.5〔A〕 ×3〔V〕 = 4.5〔W〕に なる。電力の大きさが1になるので、水の上昇温度も 1/4に = 3 〔A〕 なので、電力 なる。 図3より6Vのとき、電流を5分間流すと8℃ 上昇して いるので,3Vのとき、電流を5分間流すと2℃上昇するこ とがわかる。したがって (0.0) と (52) の2点を通る直線 を引けばよい。 (4) 並列回路では、加わる電圧の大きさは一定なので水の上 昇温度は, ビーカー Ⅰ >ビーカーⅡIである。 また, 直列回路 では, 流れる電流の大きさは一定なので、電熱線Aに加わ る電圧よりも電熱線Bに加わる電圧の方が大きいため、水 の上昇温度は, ビーカーⅣ>ビーカーⅢである。 直列回路全 体の抵抗の大きさは, 4 + 2 = 6 [Ω]なので, 回路全体に流 6 (V) =1 [A] であるから, ビーカー 6 [Ω] れる電流の大きさは, Ⅳの電熱線Bの電力は4W。 ビーカーⅡIの電熱線Bに流れ 6 〔V〕 = 1.5 〔A〕 なので, 電力は9W で 4 [Ω] る電流の大きさは あるから 水の上昇温度は, ビーカーⅡI>ビーカーⅣVである ことがわかる。したがって, 水の上昇温度を大きい順に並べ ると, I > ⅡI>Ⅳ> ⅢIとなる。 図 消費電力が から1つ選び、 何Jになるか。 電熱線 B (4Ω) BAX3V A (① 電熱 熱 電熱 電熱

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English Junior High

下線部(1)を並べかえてくださいm(_ _)m

"How are you?" is a nice question. It's a friendly way that many people greet each other. But "How are you?" is also a very unusual question. It's a question that often doesn't have an answer. s "How are are you?" the When a person meets a friend on the person doesn't really want to hear an I with wrong what is (1) (7 me street and asks answer such as "I really don't know I thought I had a cold. ). I took some medicine, but that didn't help much, so I have to go to a hospital." The person who asks "How are you?" wants to hear the answer "Fine," even if the other person isn't ( 2 )! The reason is that "How are you?" isn't really They are simple ways of greeting a (3 ), and "Fine" isn't really an answer. people and saying "( 4 )” boog aleat Sometimes, people also don't say exactly what they mean. For example, when someone asks "Do you agree?," the other person might be thinking "No, I disagree. I think you're wrong." But (5) it isn't very polite to disagree so strongly, so the other person might say, “I'm not so sure." L say that you don't agree with someone. It's a nicer way to savongob a gni People also don't say exactly what they are thinking when they finish *conversations with other people. For example, many con conversations over the phone end when one person says, "I have to go now." Often, the person who wants to "I have finish the phone conversation gives an excuse: "Someone's at the door." to *put away the *groceries." "Something is burning on the stove!" The excuse might be real, or it might not be. Perhaps the person who wants to finish simply doesn't want to talk any more, but it isn't very polite to say (6) that. The excuse s more polite, and it doesn't hurt the other person's feelings. *Whether they are greeting each other, talking about an opinion, or ending a onversation, people often don't say exactly what they are thinking. mportant way that people try to be nice to each other, and it's all part of the ame of language! It's an * (Express Ways 2, Pearson Longman -

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English Senior High

答えがなく困っています。 どうかよろしくお願いします。

Ⅰ 次の英単語で最も強く発音する部分(第一アクセント)を、 それぞれ記号で答えなさい。 d 2. a-bil-i-ty 3. access 4. va-ri-e-ty 5. in-tro-duce del-i-cate アイウ アイウェ アイ アイウェ アイウ Ⅱ 次の英文を読み、 設問に答えなさい。 How many hours a day do you spend on your *cell phone? Today, more and more young people are spending more and more time on smartphones and computers. According () a 2013 *survey carried out by the *Japanese Cabinet Office, 97.2% of high school students owned a cell phone; of these, 82.8% had a smartphone. This is a *drastic increase from 2010, when only 3.9% of those with cell phones had smartphones. The survey also shows that the spread of smartphones has led to increased access to the Internet among children, whose average access time on a weekday is 107 minutes. The Cabinet Office also found that 40% of Japanese children *log on to the Internet more than two hours a day, and that 8% spend more than five hours a day online. This has led to some serious social and *psychological problems. Heavy Internet users become *obsessed with staying online and develop an *addiction to games, social media sites, and free communication systems such as LINE. The various *adverse effects of such addictions have been reported in most developed countries. Many young addicts suffer (2) headaches and sleep disturbances such as *insomnia. They fail to maintain normal weight *due to eating irregularities. And many are more likely to experience emotional distress, isolation, anxiety, and depression. A British study suggests a clear link between excessive Internet use (3) lower self-esteem. Those young people who spend more than A four hours a day looking at a screen are particularly *vulnerable to mental *disorders. -No H Several related studies conducted in China make clear the effects of Internet use on brain structure. One study has shown that *volume @losses were seen in the *gray matter areas of Internet addicts' brains. These areas are involved in people's ability to develop *empathy and compassion for others. Another Chinese study used MRI scans to look at the brains of Internet-addicted teenagers and found significant damage in the *white-matter nerve fibers connecting the brain areas governing emotions, decision-making, and self-control. Similar (4) can be seen in the brains of heavy alcohol and drug users. () cell phone: ## survey: drastic: 極端な log on: アクセスする obsessed with ~ : ~に夢中になる addiction due to~: ~のため volume: white matter: insomnia: TRE disorder: , empathy: # 1. ( ) ①~④に入れるのに最も適した語をそれぞれ一つずつ選び、その記号で答えなさい。 (with into A to = at) 2 ( from = above) □in Japanese Cabinet Office: A psychological: 心理的な . # adverse effects: vulnerable to~: ~になりやすい gray matter: K ハon

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Mathematics Senior High

三角関数の和積の公式を用いる問題なんですけど、 計算がどうなってるのかが分かりません💦 解説お願いします🙏

240 基本 例題 152 (1)積→和,和→ (7) sin 75° cos 15° 8-A 解答 (2) △ABC において,次の等式が成り立つことを証明せよ。 FAOB- OP 0+ sinA+sinB+sin C=4 cos mia. H-1A+B+C=xから、最初にCを消去して考える。 そして,左辺の sin A + sin B に 和積の公式を適用。 和と積の公式 積の公式を用いて,次の値を求めよ。 () sin 75°+sin 15°=2 sin- ! ゆえに (1) () sin 75° cos 15°= {sin (75° +15°)+sin(75° — 15°)} 2 = 1/ 4 よって -cos 80° + (2) A+B+C=²5 (1) sin 75°+sin 15° ( cos 20° cos 40° 75°+15° 2 2 2+√3 (sin 90°+sin 60°)= (1 - 1/ (1+√3)= ² + 1/3 2 4 2 1 cos 80°-- -c 4 COS p)nie+(849) 1 cos 20° cos 80°= 4 cos 80° + = () cos 20° cos 40° cos 80°= (cos {cos 60°+cos(-20°)}cos 80°= 1/2 (21/12) +cos 20° 2 sin A+sin B+sin C=2 sin- (8-30) 200- =2 sin = 2 cos 4 co 75°-15° 2 (2) △ABCにおいて 海の等 A+B 2 A+B 2 A 2 cos- PRESE 16-wale (8+1)niel C= π-(A+B) +18+28 sin C=sin(A+B), cos= cos(+/- A+B). 2 20 COS cos A B C / cos COS 22 p.239 基本事項 ①1 ② 1 1 cos 80°+cos 100° += cos 80°+cos (180°-80°) + 1 8 4 8 1 1 8 8 =2 sin 45°cos 30°=2. onle=(8-)nie -cos 80° + COS •2 cos A-B 2 COS Apogonie 80 ng =8) 2001-201 2 B cos cos 1 1 2 2 ● (1) cos 105°-cos 15° A-B 2 B Acos(-) 2 200) |=sin- +sin 2. TAOR +cos A <RAOR A+B 2 -{cos 100° +cos(-60°)} +y)+tan( A+B 2 A+B 2 √2√3 2 2 24 N 2 2. mie satu cos 80° 練習 (1) 積和,和→積の公式を用いて,次の値を求めよ。人分1② 152 (7) cos 45° sin 75° (1) sin 20°. 90+01

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