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English Senior High

mainstreamⅢ chapter18 章末問題 解答教えてください!

6 Chapter 18 Comprehension a. On the basis of Gurdon's research, Yamanaka revealed that specialized cells from a mature Choose the appropriate answer. body can be transformed into iPS cells. frog. b. Gurdon placed cells from the skin of mice into an unfertilized egg cell of a c. Yamanaka took cells from the blood of mice and transformed them into a baby. d. The only difference between Gurdon's and Yamanaka's experiments was what cells they used. e. Organ rejection will no longer be a problem because it has become possible to develop organs from the patients' own cells. f. iPS cells will soon make it possible to cure all types of diseases. g. Yamanaka admits that iPS technology has done harm in some cases. h. Even as a scientist Professor Yamanaka believed that his mother saw his father's ghost. i. Professor Yamanaka has never thought of giving up research. found iPS ce j. What Professor Yamanaka wanted to say in the speech was what seems unfortunate at first may turn out to be fortunate in the end. not e mes B Choose the most appropriate main theme. a. John Gurdon and Shinya Yamanaka won the Nobel Prize because they helped each other for 40 years to create iPS cells. Chapter 18 | Minis SO 15 b. We should be careful about new technology because it takes time to put it into use and it can do harm. 24 c. Professor Yamanaka has experienced challenges in his life but they were also opportunities, one of which led to the Nobel Prize.

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English Junior High

暗くてすみません💦 1〜3まで教えてください🙇‍♀️🙏

3 次の英文は, 南中学校に通う瑠美 (Rumi) が学生ダンス競技会 (the Students' Dance 'Competition) について, 得点の表 (Table) を作り, 英語の授業で発表したときのものです。 1~3の問いに答えなさい。 I'm on the school dance team. We had the Students' Dance Competition last Saturday, and eight dance teams from the junior high schools and high schools in our city performed. We didn't think we could win the dance competition, but we came in third overall. Please look at this table. It shows the scores of the top three dance teams. Igawa High School got the best score of the three teams for 5 dance technique, but they came in second overall. They danced very well, but they didn't smile enough. They needed more expression. In contrast, Heisei High School didn't get a high score for dance technique, but they got 86 points for dance expression. They were dancing with smiles. I enjoyed their dancing. To my surprise, we got better score than Heisei High School for dance expression. We started practicing for the dance competition two months ago. We practiced after school and on weekends to win the dance competition. We enjoyed dancing at first, but a month ago, we didn't enjoy it. When we were dancing, our English teacher, Mr. White, came to us and said, “Enjoy dancing! Relax more and dance with smiles. When ( ① ), the audience doesn't enjoy your 15 | dancing.' We found we didn't enjoy dancing. We practiced only to win the competition, and we forgot the most important thing. On the day of the dance competition, we danced with big smiles and got a good result. I will enjoy everything with a smile. (注) dance : ダンス, ダンスをする high school: 高校 perform: 演じる overall: 総合で score : 得点 top: 上位の technique : 技術 (力) expression: 表現 (力) in contrast : 反対に point : 点 to my surprise: (私が) 驚いたことに come in ~: ~位になる smile : ほほえむ, 笑顔 at first 最初は relax : リラックスする audience : 観客 result : 結果 1 瑠美が発表のときに見せた表として最も適切なものを、 次のア~エの中から一つ選び、 そ の符号を書きなさい。 ア イ Table 技術力 表現力 (100点満点)(100点満点) 平成高校 78 86 井川高校 76 82 南中学校 68 86 Table 技術力表現 (100点満点)(100点満点) 平成高校 72 86 井川高校 81 76 南中学校 68 86 Table 技術力 表現力 (100点満点) (100点満点) 平成高校 78 86 井川高校 82 76 南中学校 68 87 1. An important thing 2. Practice 3. Result イ 2 本文中の( ① )に入れるのに最も適切なものを、次のア~エの中から一つ選び、その 符号を書きなさい。 I ア you don't dance well イ you don't enjoy dancing ウ you dance well I you enjoy dancing 3瑠美の発表の流れとして最も適切なものを、次のア~ウの中から一つ選び, その符号を 書きなさい。 ア 1. Result 2. An important thing 3. Practice 10 Table 技術力 表現力 平成高校 (100点満点) (100点満点) 80 87 井川高校 81 76 南中学校 67 86 ウ 1. Result 2. Practice 3. An important thing|

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Mathematics Senior High

[2]なんで0を含まないのですか?

142 00000 基本例題 90 ある変域で不等式が常に成り立つ条件 0≦x≦2の範囲において、 常に x²-2ax+3a> 0 が成り立つように、定数 αの値の範囲を定めよ。 CHARTO SOLUTION 解答 415600 ある変域で2次不等式が常に成り立つ条件 2次関数のグラフから読み取る ある変域でf(x)>0 (変域内の最小値) > 0 変域に制限があるから,xの係数> 0 かつ D<0 だけで済ませてはダメ。 問題をグラフにおき換えると, 求める条件は 「y=x2-2ax+3aのグラフが 0≦x≦2の範囲でx軸の上側にあること」 である。 これを(変域内の最小値)>0と考えてみる。 この最小値の求め方は、基本例題 62 (p.104) を参照。 y=x-2ax+3a のグラフは下に凸であるから、軸が変域の左外,内,右外で場 合分け。 f(x)=x2-2ax+3a とする。 求める条件は, 0≦x≦2の範囲における関数 y=f(x) の最小 値が正であることである。 f(x)=(x-α)2-α² +3a であるから, y=f(x) のグラフは下 に凸の放物線で, その軸は直線 x =α である。 [1] α < 0 のとき f(x)はx=0 で最小となる。 よって RES f(0)=3a>0 これは,α<0 を満たさない。 [2] 0≦a≦2のとき f(x) は x=αで最小となる。 よって f(a)=-a²+3a > 0 これを解くと, a(a−3) < 0 から これと 0≦a≦2の共通範囲は [3] 2 <a のとき f(x) は x=2で最小となる。 よって f(2)=4-a>0 これと 2 <a の共通範囲は 2<a<4 ② 求めるαの値の範囲は、①と② を合わせて 0<a<4 すなわち 0<a<3 0<a≦2 640 ゆえに a<4 PRACTICE 90 f(x)=x²-²¶r-atu 消してるからに ありえる ceco sta a²-3a<0 coa 4 JETHAL [1]\ a [2] [3] 0a2 02 a 2x

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