Grade

Type of questions

English Junior High

1のQ4と2を全部教えて欲しいです(>人<;)

Program7 A Gate Way to Japan 1. 真央とダニエルの会話を読んで、 問いに答えなさい。 Mao: Hi, Daniel. You look happy. Did something good happen? Daniel: (just / from /have/ gotten / my uncle / an email / I) in Italy. Mao: Your uncle in Italy? What does he do there? Daniel: Ah, he's a sportswriter. He loves Japanese pop culture like manga and anime. Mao: Great! Are Japanese manga and anime popular in the U.S. too? Daniel: Yes. The words manga and anime are (P) in English. Mao Like sushi and kimono? Mmm, interesting. By the way, I'm going to do my homework for the speech after I get home. Have you (1) it yet? Daniel: I started it yesterday, but I (2) finished it yet. Mao: What are you () about? Daniel: About Captain Tsubasa. My uncle recommended it. Mao: Do people in foreign countries know about Captain Tsubasa? Daniel According to my uncle, a lot of professional soccer players watched it when they were children. Some of them started ( I ) soccer because of it. Mao: Wow! Captain Tsubasa gave them "wings." Q1 かっこ① の単語を並べ替えて、本文の内容に合うように英文にしなさい。 Q2 (ア)~(エ)に入る語を下から選び、それぞれ適当な形に変えて書きなさい。 play write do use Q3 かっこ②に入る単語を下から選び、 記号で答えなさい。 didn't haven't 5, am not Z. can't Q4 英語の問いに、 英語で答えなさい。 What does Daniel's uncle love? 2What does the word "wings" mean? ● 2. 日本のポップカルチャーについての発表内容を読んで、 問いに答えなさい。 Manga and anime are parts of Japanese pop culture. Today they attract and influence many people around the world. I've read a book about art history before. There was a similar situation about 150 years ago. In those days, ukiyo-e was pop culture like manga. It became very popular in Europe. Have you ever heard of Monet and van Gogh? They were greatly influenced by ukiyo-e. Japanese pop culture is getting more popular day by day. It is a gateway between Japan and other countries. Q1 下線部 ①~③は何を指すか、 下から選び、 記号で答えなさい。 あ、 Manga and anime 1, Japanese pop culture う、 art history 7, Monet and van Gogh ukiyo-e Q2 英語の問いに、 英語で答えなさい。 What became popular in Europe about 150 years ago?

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Chemistry Senior High

(2)から(4)まで解き方がわからないです。 画像中の解説では理解が出来なかったので分かりやすく教えて頂けると幸いです。お願いします!!

APINGAT STIMULO, HUG 例題 ⑤ 電離度と濃度 5 0.10mol/Lの酢酸水溶液がある。電離度を0.010として次の(1)~(4) の濃度を求めよ。(金) (1) 水素イオン濃度[H+] (2) 酢酸イオン濃度[CH3COO-] (4) 水酸化物イオン濃度[OH-] (3) 酢酸分子濃度[CH3COOH] |解説| cum CH3COOH - →H+ + CH3COOO (2) HOBK&Hしたと 酸c 0 OHN (6) 1つは 電離前 電離後 (1-α) (1) 「イオンはカモ電」を使う。 酢酸は1価の弱酸より, [H+] = 1 × 0.10 × 0.010 = 1.0 × 10-3mol/L (エ) よるの森 Hen(d) ca 1.0 × 10-14 [H+] 電離前 (オ)0年) (2) 酢酸の電離式は, CH3COOH CH3COO+H+だから, [H+]=[CH3COO-] となり [CH3COO-]=1×0.10×0.010=1.0×10-3mol/L/に近い (3) 電離せずに残った [CH3COOH] は, 初めの濃度から電離した分を引けばよい。 = 水 OeHold Dom (02.(s) D. CHICO C (I) < (RC) < (C) < (F) () <() () [H+][mol/L] = (価数) × (モル濃度) × (電離度)より,倍に濃くする。 0 えて薄め [CH3COOH]=0.10-0.10×0.010=0.10×(1-0.010)=9.9 × 102mol/L Ricmomo [H] (4) [OH-]は, 水のイオン積[H+][OH-]=1.0 × 10-14 (mol/L)2より、 toner [OH-]= CH3COOH 2+1 FORD 1.0 × 10-1400 = 1.0×10-11mol/L 1.0 × 103 ので 0.10 HOC 電離後 0.10(1-0.010 ) 解答 (1) [H+]=1.0×10-3mol/L XOHq ( na α = 0.010 COULD OOK 157~8-30+ OBA の味中 個円 (3) [CH3COOH] = 9.9 × 10-2mol/L LITOL LITOL, SIMOLEST (0) XH&m H+ CH3COOH 10:30 10倍濃くなり), pH=5-3=2 0 THE & 0 HUN 1 x 0.10 × 0.010 1 × 0.10 × 0.010 HO. (2) [CH3COO-] = 1.0 × 10-3mol/L Luty (SPC (4) [OH-]=1.0×10-11mol/L TEEKLINIKAH MARO

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