Grade

Type of questions

English Senior High

(6)の模範解答が⭕️なのですが、問題文にはwhen Nightingale was young とあり、文中の黄色マーク🟡で引いた該当する文は、彼女が30歳になった時のことを言っているのから❌ではないのですか?教えてください🙏😭

次の英文を読んで、(1)~00までの文がその内容とあっていれば〇をそうでなければ×を解答 用紙に記入しなさい。 Florence Nightingale Florence Nightingale was born on May 12, 1920, into a wealthy family in England, and received the most luxurious education from an early age, learning not only foreign languages like French, Greek, and Italian, farmers she visited for charity work, she gradually began to think that she wanted to work in a job that but also mathematics, astronomy, psychology, and literature. However, after seeing the lives of poor served people. When she turned 30, she decided to become a nurse and started working at a hospital in London. Nightingale, who eventually became a director of a women's hospital, began to advocate the need for nurses with specialized training. At that time, nurses had a low status and were considered nothing more than servants who cared for the sick. A major turning point occurred in 1854. War began in Crimea*, present-day Ukraine, and Nightingale was sent there with 24 Catholic sisters and 14 nurses. Nightingale's efforts improved the hospital environment during the war. The Nightingale School of Nursing was established with the Nightingale Fund created during the war. Although Henri Dunant, a founding member of the International Committee of the Red Cross, highly praised her work, Nightingale was not involved in the International Committee of the Red Cross. This was because she believed that aid activities based on self-sacrifice by participants would not last long. Her famous quote, "Devotion without sacrifice is true service," expresses this well. It is said that this was due to the idea that "we rely on the spirit of service of our members, but without financial support, we are powerless." Nightingale only served wounded soldiers as a nurse for only two years during the Crimean War*, and became famous for her symbolic image of dedication and for her use of statistics to reform health care. The statistical methods she used at this time were highly praised, and she was considered a pioneer of statistics in England. Nightingale suffered from poor health from a young age, and is said to have spent most of her time in bed after returning from Crimea. Nightingale passed away peacefully at the age of 90 at her home in London on August 13, 1910. advocate* 主張する Crimea* クリミア半島 Crimean War* クリミア戦争 (1) Florence Nightingale was born in a wealthy family and she learned many foreign languages. (2) Nightingale wanted to be a nurse when she was small. P (3) It was when she was 30 years old that Nightingale wanted to be a nurse and started working at a hospital. (4) Nightingale's work in Crimea improved the environment of the hospital there. (5) Nightingale did great work to found the International Committee of the Red Cross. (6) When Nightingale was young, nurses were thought to be like servants. (7) Nightingale's famous words, "Devotion without sacrifice is true service," means self-sacrifice of the participants is always necessary rather than financial support. (8) Nightingale was not blessed with good health since young and spent much of her time in bed. (9) Nightingale is considered a pioneer of statistics in the world as she used statistics to reform health care. (10) Nightingale worked as a nurse all her life.

Resolved Answers: 1
Mathematics Senior High

高一数学です。(2)がわかりません。なぜ絶対値なのに二乗するんですか?

基本 例題 43 対偶を利用した命題の証明 文字はすべて実数とする。 対偶を考えて,次の命題を証明せよ。 (1)x+y=2 ならば 「x≦1 または y≦1」 (2)2 +626 ならば 「|α+6|>1 または |α-6|>3」 CHART & SOLUTION 対偶の利用 00000 p.76 基本事項 6 2章 6 命題の真偽とその対偶の真偽は一致することを利用 (1)x+y=2 を満たすx, yの組 (x, y) は無数にあるから,直接証明することは困難であ る。そこで,対偶が真であることを証明し, もとの命題も真である, と証明する。 条件 「x≦1 または y≦1」 の否定は 「x>1 かつ y>1」 (2) 対偶が真であることの証明には、次のことを利用するとよい。 解答 A≧0, B≧0 のとき A≦B ならば A'≦B2 (p.118 INFORMATION 参照。) (1) 与えられた命題の対偶は 「x>1 かつ y>1」 ならば x+y=2 これを証明する。 x> 1, y>1 から x+y>1+1 すなわち x+y>2 よって, x+y=2 であるから, 対偶は真である。 したがって,もとの命題も真である。 麺 (2) 与えられた命題の対偶は 「la +6≦1 かつ a-b≦3」 ならば2+b2<6 これを証明する。 ←pg の対偶は g⇒ b ←x>a,y>b ならば x+y>a+b (p.54 不等式の性質) 0 論理と集合 = 0 される |a+6|≦1, |a-b≦3から (a+b)≤12, (a-6)²≤32 ←|A|=A2 >1 よって (a+b)2+(a-b)2≦1+9 ゆえに 2(a²+b²)≤10 よって a²+b²≤5 ゆえに、対偶は真である。 したがって,もとの命題も真である。 ← ' + b'≦5 と 56 から a2+62<6 S POINT 条件の否定条件p, gの否定を、それぞれp, gで表す。 かつ または -PNQ=PUQ またはq かつ PUQ=PnQ PRACTICE 43° 文字はすべて実数とする。 次の命題を, 対偶を (1)x+ya ば 「xa-b または y>b」 (2)xについての方程式 ax+b=0 がただ1つ して証明せよ。 もつならば

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