(5) S√³ 2x + 1 d
+1
√3 2x
√3
dx = SY²³
d x + √√³.
1
2
x² +1
2x
2
x² +1
CO
√3 (x²+1)'
2
dx = S₁
-dx
x² +1
2
1
x² +1
-[log(x+1)] = log2
2
=
また, x=tan とおくと
dx=-1² do
x
xH
1 → √3
2
π
π
√3
1
•7-1
0
S
[₁ +² +1
-dx
4
3
1
1
1
-S₁tan's +1' cos³0 = [1₁ - 12
do [0]
tan²0
T
√√3 2x+1
したがって 241 dx = log2 + 12
1
x² +1
o
Hie+x200
-dx
