ノートテキスト
ページ1:
Electrical Circuits & Electronics Quantities & Units Scientific Notation Engineering Notation prefixes ax 10" (1≤a <10) a x 10 ( n 为 3 的倍数) pico P 10-12 one-trillionth nano n 10-9 one-billionth micro u 10-6 one-millionth milli m 10-3 one-thousandth kilo k 10 one thousand mega M 10% one million giga. G 10° one billion. tera T 1012 one trillion Electrical Units: QUANTITY SYMBOL UNIT SYMBOL capacitance 电容 C farad F charge Q coulomb C conductance 电导 G siemens S current 1 ampere A energy W joule J frequency f hertz Hz impedance 阻抗 Z ohm 2 inductance 电感 L henry H power P watt W reactance 电抗 X ohm 02 resistance R ohm 92 voltage V volt V Measured numbers Significant digits (有效数字): @所有非零 非零 问。 → 有效 前缀。 2 12000 (2) 后缀。 => 有效 ex 1.20×10 (3) @整数后0 > 不定 Rounding off ( x) Electrical Safery: body Current 0.4 mA 1.1 mA resistance => 10k ~50k Physical Effect Slight sensation Perception threshold Severe painful shock, muscular contractions, breathing difficulty 1.8 mA Shock, no pain, no loss of muscular control 9 mA Painful shock, no loss of muscular control 16 mb to ma Painful shock, let-go threshold 23 mA 43 MA 75 mA 235 mA 4,000 mA 5,000 mA Tissue burn Ventricular fibrillation, threshold Ventricular fibrillation, usually fatal for duration of 5 s or more Heart paralysis (no ventricular fibrillation) ↑ ↑ M Touchpotential Step potential Shock hazard path Touchpotential
ページ2:
二、 Voltage Current, Resistance 1 ec. = 1.6 × 10-19 C -> 1 C = 6.25 × 10 e.c. =>> Q Voltage ' W V (Volt = 1) Q number of e 6.25×108 sources : Batteries Solar Cells Generators 10 e 光一电 机电 AC voltage Electronic power supplies DC voltage Current I Resistance: R = Q (AC) t V (Q) Heat → collisions of e- atoms Resistors Resistor color code: 1st digit Conductance (+): reciprocal of R (Siemens) R 0 Black 1 Brown 2 Red Percent tolerance 3 Orange Multiplier digit (Number of zeros Yellow following 2nd digit) 5 Green 6 Blue 680 ±5% 7 Violet 8 Gray 9 White Resistor label code : 1. Numberic : 123 12,000 12 k 1st digit 2nd digi Multiplier (Number of zeros) • Variable Resistors 。 Potentiometer + - divide valeage control Current 三 • Rheostat - electric Circuit ±5% ±10% ±20% Gold Silver No band 2. Alphanumeric 22R -220 and makiplier R (1) / K (10% or 10³) / M (10%.. 10%) Ist digit 2M2 Decimal point and mahiplier 2nd 2.2 M 220K-220k 3rd git Shaft Wiper Output (wiper) terminal Resistive element Circuit voltage source Closed circuit (通路) Current path load / Open circuit ( ) 2/ Short circuit (短路) (a) Potentiometer (b) Rheostat (c) Potentiometer connected as a rheostat Closed switch
ページ3:
Switches Lamp 1 SW O Toggle switch Rocker switch Push-butos switches PC board mounted push-button switches (a) SPST (b) SPDT (c) DPST (d) DPDT (e) NOPB (D) NCPB (g) Single-pole rotary Rotary whe DIP switches forming on PC bonds Protective devices: (a) Cartridges ~ the Plug fuse (c) Circum breakers id Fose symbol Clecsit breaker Wires: Resistance R R- Cross-sectional area, A L cross -sectional area A = (CM circular mil (mils)") -0.001 in. 1 mil = 0.001 inch A=1CM Ground: 当参考点(reference point) ⇒ 0 V + b (ex) +12 V (a) (b) (c) OV Measurements Ammeter (series) Voltmeter (parallel I) (out of circuit) 四、 Ohmmeter Energy Power Ohm's law : . Energy V = IR . Power: P = W (Watt - Joule ex W = (0.25 W) (4hr) = 1.00 & wh E Kilowatt-hour (kWh) P=IV=IR = R Power Rating of resistor:(功率額定) : physical composition size. shape ohmic value (x) (0) (0) (0) diameter = 0.005 inch = 5 mils. A = d` = (5 mils) = 25 CM
ページ4:
Power Energy conversion energy rating ―>> Voltage drop heat e:number(不变)、 Power supply Ampere - hour = rating Pout Pin energy (Ah) (故障排除): (V) efficiency Troubleshooting analysis planning measuring 五、 damage ex For how many hours can a battery deliver 2 A if it is rated at 70 Ah? 70 Ab/2 A-35 h Series Circuit Series ($) I相同 V . R = = V₁ + V. ... R₁ + R₁₂+ • Kirchhoff's Voltage law ↳ Voltage divider :) Voltage R Measurement : P = P₁ + (KVL) 封闭迴路 Voltage 总和为。 Troubleshooting series : open short ⇒ prevent current >>>> cause more current 557 333 Potentiometer as an Adjustable Voltage Divider
ページ5:
六 Parallel : . Parallel Circuit (並) P = P₁ + P₁₂+ V相同 1 R = I. + I. ... R₁ R₁ @ Kirchhoff's Current law (KCL) G = G,+G+ 流 入 总 I = 流出总I node 13 I.-1.-1. ↳ Current 12 divider: Ix = (RE) IL Troubleshooting parallel Rx : open R₂ I₁ = R₁ + R₂' 两电阻特例 R₁ I₁- I R₁ + R₂ Rand 1 I\ 分支工 不变 t Series - Parallel circuits Loaded voltage divider : 10 V 1.0 k R₁₂ R 1.0 kn 10 V VOUT 1.0 k R VOUT 1.0 kn (a) Unloaded R₁₁ Vout = 1 V... R₁+ (b) Loaded The effect of a load resistor: VOUT YOUT ww (b) R not significantly greater than R₂ (c) R₂ much greater than Ry Your VoUT load) . Load current / Bleeder current (I) Loading effect of Voltmeter R₁ ww (b) R₁ w ww R,RM • if meter resistance 至少比连接电阻大十倍 => loading effect J SV Notation for Parallel Resistors R₁ || R2 || R3 || R4 || Rs 24 V (1 unloaded: Voxt " ( 4.1 + 10) 5 = 3.40 V m R₁ll R₁ = 16 b (4) loaded: 10 k R₁ 12 k RLL 6.2 k R R₁ R₁₂ 6.2 kn 100 k BLEEDER W R 100 k W . 1-52.22 √
ページ6:
Wheatstone bridge :) R₁ VOUT R₂ m R4 · balanced : V₁ = V₁ Vout = 0V => = 1 V₁ = V₁ measuring temperature : ≈ AVOR A Rehern V (- ) 4R Thevenin's theorem : (數理學文理) 简化电路成串联电路 Thevenin's equivalent valoage (VTH) AB 1] open circuit (no load) V Thevenin's equivalent resistant (Rin) - AB同总R(所有換成门电阻) ww • step: 负载廾路 Maximum Power Transfer theorem : thevenizing bridge circuit Max transferred to power load when R₁ = Rs w V₁ V₂ V₁ V4 (e) Thevenin equivalent circuit W Source RS www = R 2 R, R. = R.R (可測未知) black box ww A RTH = m RL P = IV₁ = I'R = V theorem (重整定理): Superposition multiple voltage/ current sources 每个源分开看,再叠加 (a) Problem: Find Troubleshooting open → 022 short => 002 (d) Find due to ww w (Find due to g ( partial open →>> much higher partial short much lower (R) do Restore the original sources. Algebraically add an Past the actal they are in same direction PmW)
ページ7:
Sine ^\. Alternating Current & Voliage] wave (正弦波) Polarity (#21) Positive nation . Peak value (4 1) : Vp/ Ip ↳ peak. to -peak value : Vpp = 2V₁ / IP Act AC之熱能(power)等效于 DC之大小 • RMS value (root mean square effective value) 等效值 -> = Vrms VP ≈0.707 Vp V₁ = √ √₁ = 1.414 Vrms => VIP . Average value Vavg - Vp angular measurement ≈0.637 Vp Irad-57.3" radius S = r . formula: y = A sing . Phasor (10) 180° 90° 135°℃ 225°-- AC circuit : 270° 90° 135° 315 ≈ 2.828 Vrms /I月理 Half-cycle average value 0637 1809 90/2 rad √ 225° 270° 315° 360° 360°,2 rad 90° . phase shift =V sin 6 0-45 45° +Voltage (+V)† current (+1) Positive maximum -Voltage (-V) current (-) Negative maximum SA A leads B by 90°, or B lags A by 90. . Ohm's law . Power Kirchhoff's law. ⇒>> 換RMS仍适用 (Vrms Irms RP=Iws Vim = IR = V ...) superimposed DC & AC Nonsinusoidal wave VDC+V₂ VDC RV + VDC Voc-V 0 Pulse wave: (脈波) pulse transit rapidly (leading or rising edge) from baseline to amplitude level, after a period of time, transit rapidly (trailing or falling edge) back to the baseline level Time (1) v = Vp sin e i = Ip sine
ページ8:
Square • ideal pulse T Amplitude Leading (rising) edge Leading (falling) edge Trailing (falling) edge Trailing (rising) edge Baseline 土 Baseline Pulse width (a) Positive-going pulse - ideal pulse non- D 八 (b) Negative-going pulse time interval → 10%~ 90% of Amplitude • pulse width > half. -way point repetitive pulse (periodic) wave → kw ) 100% (佔空比) T dury cycle - 12 K to to 0.1A- duty cycle 50% the average value of pulse wave Vavg = baseline + Sawtooth wave · ( duty cycle) ( Amplitude) (三角/锯齿波) triangular ⇒> two ramps slope 19 |½/2T|T| Triangular ramp (linear) sawtooth 九、 basic V (or 7) Slope Nonalternating Triangular Alternating Triangular => Two ramps duration 不同 V (or /) Alternating Sawtooth Slope (a) Positive ramp Capacitor () (b) Negative ramp construction : Dielectric 介視角 how to store Conductive plates charge insulating material as the capacitor charger Connecting leads After the car charges to Voelectrons fre deally, the capacitor charge when cted from the voltage s Q volt >> per C (Farad = Cul) ✓ Capacitance (电容): amount of charge stored 44 µF (10) PF (10°) sawtooth (sweep) voltage
ページ9:
how to store energy: 以电场儲存 W = IC V² (J) Lines of force F = ko.0. 1 mil = 0.001 inch Capacitor Rating : voltage rating (breakdown / working voltage). 不损害设備 Man voltage ⇒ dielectric strength 决定(1) mil temperature coefficient. +: T/ ⇒ C : T' ⇒ CA Leakage: 厶介电质非ideoad 会漏电流 c= physical characteristics : . dielectric constant (relative permittivity) == (8-85×101) C = d [types Fixed capacitor 1. Mica (元) : capacitor. type 2. Ceramic capacitor = 6.= 真空:6=8.85 × 10-h (F/ml (a) Full plate areac (b) Reduced plate area (a) Plates closer together. (b) Plates further apart more capacitance less capacitance more capacitance less capacitance - stacked foil · mica / silver screened (a) Stacked layer arrangement bo Lapers are pressed together 1 pF ~ 2.2 uF • E1 > 小物理尺寸供大C 3. Electrolytic capacitor 有极性⇒ 反会损坏 1 ~ 200000 uF 350 V (b) Typical radial-lead electrolytics type - Al / Ta Variable capacitor • Ceramic or Mica is common dielectric C changed by plate sparation (PR #RUE) Capacitor Labeling: (小型) 有标一 AF(MF、MFD) 有小数 μF 纯数字 三位、无小数 ab x 10° (c) Symbol for an electrolytic capacitor. (0.022 0.047 0.001 MFD 220 (a) (b) (c) (d) (a)0.022F (b) 0.047 F (x)0001 (d) 22 p
ページ10:
Series capacitors · / V₁ = V + V, + ... / O . CV CV+CV+... = V-V = Parallel capacitors: Q = Q, Q₂+ +... ../ C.V. = C.V, + CV, +... capacitor in DC circuit 连DC => 充电 Q 1 + C₁ = C, +C₁₂+ Charging . 充滿 no current 10 open Discharging . capacitor blocks constant DC c. 2 (a) Uncharged 50 V C. C₁ = CICLI Fewer electrons More electrons B more positive make plate B more negative (b) Charging OV (a) Retains charge (b) Discharging (c) Uncharged .0 (c) Fully charged RC time constant: . . charge 移动需时间 take 57 to general formula: => time interval: time constant 7 = RC V (final voltage change Charging carve with percentages of the final volage V by 99% transient time Exponential voltage curves v = V+(Vi-V) e i = IF (I-IF) e v = V₁+(0-V₁) e = V (1) L charging from 0 L discharging to 0 v = 0 + (V₁-0)eth. V₁.e final/initial AC circuit capacitor in 瞬时电流 i Capacitive 1 = C 1/ Reactance ( Xe容抗】 A Vc lags I 90° 2xfc (2) 1 Ohm's low : VIX rate of change EM (d) Retains charge Vinitial voltage by Discharging curve with percentages of the initial voltage C = 1
ページ11:
power: #cycle 部分 儲存 energy 另一部分稈回电源 instantaneous power piv Ptrus = 0 = 电容不耗 Energy V reactive power 电容 store or return 之 rate -> PIVX₁ == (VAR) Xc applications: Filtering - power supplies DC blocking / AC coupling - not pass DC Power line decoupling - supply suppress unwanted voltage spikes due to Bypassing Signal filters # AC voltage it ww 而不 影响 DC电阻值 select AC signal Timing circuit time delay RC time constant Checking a capacitor with an analog ohmmeter. This check shows a good capacitor. + RC circuits Sinusoidal Response of RC circuit purely R • phase angle of V. I purely C 90° combination (R+C) 0°~90°间 (Impedance (F2 # ) :) Z = R+ j Xc (phasor sum) . L magnitude = + Phase angle Ohm's law : 0 = V - IZ tan X R (n) 90° fast switching Sine wave generator V leads V Velags V Fleads Xc Xc (c) (a) (b) www HH xc (a) Z = R (b) Z=Xc the =xc MMY Rectifier xp M (c) Z includes both R and Xe
ページ12:
Series RC circuit
I : 经RC相同
/ Vc tk I 90°
Parallel
V : VR 5 I
from KVL → V₁
V₂ +
0 tan
f change
:
RC
circuit:
Xc Z OR EX
R
Increasing f
Xc3
₤3
Z₂
XC2
ㄠˋ
Xev
$2
(a) As frequency is increased. Zdecreases as X decreases.
causing and to increase and decease
.
Z
RX
√R'+ X
tan" (X)
Conductance (G): G =
R
Capacitive susceptance ( 电容性电约,B،);
Admittance (Y) : Y =
=
Z
√G` + B₁"
from KCL →
=
conversion from Parallel to Series
Series - Parallel
RC circuit •
並等效成串 + $
oscilloscope
(示收器):
At
40 = (
1 x 360
T
Power
in
RC :
true PIR
reactive
P = IX
apparent PIZ
VC
Ve
Velags / by 90°.
Ve and I are in phase.
Amplitudes depend on the
particular circuit.
90°
() As frequency is decreased. Z increases as Xe increases
causing/and V to decrease and Ve to increase
Frequency is
By watching these two
meter, you can sec
what is doing: Fi
increasing and Viscos
Thus, Zis decreasing
Kb
By watching these two
met, you can see
what doing
fining and Vis
dc Thes, X
lo
☑
B=
(Siemens)
F
0
tan(+)
R-Z.co
V=
Y=VG+R
=
☑
X-Zsin
Determine (al impedance total current (c) phase angle by which Ihot leads Vs
0-0 purely resistive circuit
purely capacitive circuit
=
Pa coso =
1. V, cos
(W)
(VAR)
13xc
粒
:
--
%%₂ = {√@{ + 8% = √{\]\ <?««£}°² + (3.4[m2]} = 2.09m2
AA1000+
-
(479451)=33
X-(479) 451-339)-12)--
VV-Ve
Watts (W)
P
Voll-ampen
(VA)
P(active)
Volt-amperes
reactive (VAR)
(a) Impedance phases
(VA)
(b) Impedance phasors are multiplied by
to get power
(c) Power triangle
ページ13:
power factor : PF = cose significance of apparent power: D transferred between power source load Pa Ptrus P - 做功 #source load 12] 130 V 600w 667A this below Z-180 (Geser operating at in mits with a revival Geis in danger of internal damage dae to excess current, even though the water indicates that the power is below the maximum wattage rating RC RC . . • lead circuit phase shift Vout : circuit R √RX lag circuit Vout lage V : V... . Vout = X Von leads V. = $ = an' ( 1 ) => 4 = 90° - tan tan R # It A heat 2 energy 由 RX AB Perus P-PP P₁ Pa V Vout =Ve V (V) (phase leady Ve V (a) A basic RC lead circuit (b) Phasor voltage diagram showing the phase lead between Vi, and Your RC : 让特定频率通过 - across output R lead network - output across C lag network (截止频率)– f₁ = 2x RC (x = R of 2 f) Frequency Selectivity of high- pass filter filter low-pass cutoff frequency When RC lead network troubleshooting Ov w You (a) A hasic RC lag circuit Vout = V₁ V Determine the power factor and the true power. PF 30282 2-+-+-150 ==(15)(4258)=1 (phase lead) (c) Input and output voltage waveforms VcV -90-0 (phase lag) (b) Phasor voltage diagram showing the phase lag between Vand V (phase lag) (c) Input and output voltage waveforms RC lag network Frequency response curve for the high-pa Frequency response curve for the low-pass filter Ve? 4141 Vore d ww Ov Open R 10 V 十一、 Inductor basic inductor : (电感) 10 V m w Open Dv 10 V Ov ww 100 Ov
ページ14:
Inductance (A) : A per s through col induces / V NuA => L l how to Winding . store energy : 以磁场儲存 W = LI (J) Resistance/Capacitance (DC) Winding Resistance (R.) : 线本身R m (Henry) 00 (a) The wire has resistance distributed along its length Length, /- Cross-sectional area, A Core material Number of turns, N (b) Equivalent circuit Winding Capacitance (CW) 导线间彼此靠很近 just like c 000 Stay pance between each lop dox → 高 f 时 Cw 显著 EM induction : Faraday's law - induced V B changing rate ↳ ₤1 = induced V = 与[变化相反之 induced I ← I b Amplitude J (柳I 变化) Len's law 巨变化→ induced V (AA 抵抗原始[变化) types Des m (a) Fixed → induced V 极向产生[抵抗变化 Series capacitors . L= L, L₁₂+ Parallel capacitors mi -m (b) Variable (a) Air core (b) Iron core (c) Ferrite core . inductor | = L₁ L in + DC +... circuit constant I Rw => = no induced V V drop => 18 short P=1²Rw Conversion of electrical energy to heat due to winding resistance Energy stored in magnetic field W-L R
ページ15:
RL time constant : ·抵抗电流变化⇒不会瞬间变化 ⇒ time I reaches final value in 52 (it 63% ) . general formula: v = V+(V-V) e -¾ i IF (I-I) e -*/ constant 7 = R L charging from 0 => I₁ + (0-1₁) e = I₁ (1-e) L discharging to D => 10+ (I₁-0)e. I₁e inductor in AC circuit V leads I 90° Inductive Reactance (X感抗): . X₁ = 2xfLx Ohm's VIX₂ (D. HH) power : * cycle 部分儲存 energy 另 - 部分 釋回电源 instantaneous power piv Increasing cument in an inductor Decreasing cument in an induct true power ideally. 0 bt due to R... = P=Rw V reactive power 电 EX store or return 2 rate => Pr = IV = IX₁₂ (VAR) XL Q = P₁ Perus % = IR Rw Quality Factor : applications . Noise suppression / RF choke / Tuned circuit 十二、RL circuits Sinusoidal Response of RL : circuit Sine wave generator purely R Vlags V •phase angle of V. I purely L 90° combination (R+L) 0°~90°间 Ilags V Power curve P-V 1+ L-+ 1-0 p=0 p=v=0 p=w=0 P=0 V leads V m L
ページ16:
Impedance (阻抗): Z = R + j X L magnitude Phase angle (phasor sum) (2) : Z = R² + Xi 日 tan (L) Ohm's law V - IZ LOA (b) (c) ~ W m Series RL circuit : I : 经RL相同 V : VR 5 I / V₁ # I 90° from KVL → of change : ↳ → V₁ + V₁ 0 tan 90° I lags V2 by 90° V and I are in phase. Amplitudes depend on the particular circuit. X、Z7 日 ↑ · R 固定 Increasing f LOL Parallel RL circuit Z = RX √R+X 0 = tan" (R) R X13 X $2 Xx " Conductance (G): G= R Cal Aquency increase and Inductive susceptance (电感性电納:B): B. = Admittance (Y) : Y = → Y Z from KCL → + 0 = tan .) Series - Parallel RL circuit : 1等效成串+ Power in RL : A R-Zoove true Pere IRP cos = I.V, cos (W) reactive P = IX (VAR) apparent P₁ = I Z (VA) (a) -☑ W pieler Fancy 2 do As frogacy is deced, sad increase and decreases V₁ (b) 8 V₁. VR. VL (Siemens) a A P(apparent) P, (reactive) N By watching he twe dening Vis ant, and thesis By watching he we 1x-1
ページ17:
recall
power
factor
:
↳ significance of
power
factor
PF = cose
D
many
practical loads
本身具
=
为正常运作必需
(ex transformer
moter
speaker)
P.-I. V, cas
@ PF/ =>
1 * load
deliver
power
↳
power
factor correction :
inductive load
12
PF
並联C修正
Mo
resultant
reactive
current
=C
(a) Total current is the resultant of Ig and I
RL
lag circuit
:
Vout leads Vin
RL
V
R
√R+ X
lead circuit
:
=>
-1 x
tan
Jesh
(b) Ic subtracts from I, leaving only a small reactive current, thus decreasing
and the phase angle.
m
L
(phase lag)
VR (V)
(a) A basic RL lag circuit
(b) Phasor voltage diagram
showing phase lag between
V and Vur
(c) Input and output waveforms
w
VL (VO)
Vin
Vin
R
Vou
phase lead
(a) A basic RL lead circuit
8
(b) Phasor voltage diagram
showing V leading Vin
A
(c) Input and output voltage
waveforms
•
Vout lags V
4 = 90° - tan
"(x)
Vin
R
RL as
a
Vaut
Filter:
X₁
V..
low-
-pass
filter
{
output
across
R
fl
=> X 1
=>>
Vout / DC (0 Hz), L
act
as short ⇒
Vout = 0
output
across L
high-pass
cutoff frequency
trouble shooting
Ov
filter
f1 =
=>
Vout // DC (0 Hz), L act
as short
(截止频率)
f. - L
(x₁ = R of 2 f )
36 A
Ov
mon
Open L
Ov
DA
10 V
三
Series RLC
X tozal
RLC circuit
Zoral
==
circuit
=
+
& Resonance
=
tan (
Wental
R
m
OA
R
www
Ov
(a) Before failure
(b) After Lopens
OFA
ページ18:
Series . . X=Xc Capacitive: Inductive: Xc Va -m #m w m Xc 0 Series resonance 27fC X₁ =27fL Resonance: occures -> when ×₁ = × => 2π FL - 2xt.C effect of frequency: Ine voltage across the series combi- nation of C and L is always less than the larger individual voltage across either C or L f (resonant frequency) r f. | 21LC (4) As fequency is increased below resonance from Xe>XFincases from 0, Vic from V₁V₁ (b) At the resonant frequency, XX (a) Current . impedance . phase angle Zi IXC IX w Va in m Va m (b) Resistor voltage (c) Capacitor voltage (d) Inductor voltage (e) Voltage across Cand L combined 90 (lags V) 0° -90° (I leads V Inductor voltage and capacitor voit age effectively subtract because they are out of phase. w XL = XC Z₁ = R VR m (c) As frequency is increased above resonance: Xc<X, I decreases from V,/R. V decreases from V Ve decreases from (VRX V docremes from (VRIN, and Veg increases from 0. XcXL Capacitive: leads V Inductive: Flags V (a) Below f. I leads V.. (b) Alf. I is in phase with V. (c) Above. Flags V. (d) Phase angle versus frequency Series Resonant Filter: Band Pass Filter : Bandwidth of Passband: . BW = f-f . lower / upper cutoff frequency : f. / f₂ (-3 dB / critical band half-power frequencies) . half -power points => P(43)= I₁R = (0.7071) R = 0.5 PHAR Decibel (dB) measurement : 90 As the fini As the fency in to As the Imcy incomes from £ Ahe Inquency inces above des
ページ19:
• dB = 10 . dB Amplitude = 20 log (Post) Pin -) log (Vous) Vin (a) Actual Passhand => 0.707Vx -3 dB frequency : 20 log -20 log(0.707)--3 dB Frequencies between f, and f are passed through the filter with amplitudes no less than 70.7% of maximam Frequencies outside passband are reduced to less than 70.7% of maximam a and a are considered to be rejected. Frequencies from, and are assumed to be passed equally. All frequencies outside the passband are eliminated. Compare selectivity curves. The blue curves the greatest welectivity Quality Factor (Q) : stored Q = energy = energy dissipated Band - Stop Filter applications Tuned amplifier (b) Ideal Passhand Pr PIONE I' I'R Stephand = ✗L R (18) - 放大特定频率 Amplifier Variable C 十四 Diode (二极体) Semiconductor: semiconductive material Silicon Germanium intrinsic crystal (本做/线品 no impurities BW = Q VV 34 G₁ AE MT/ 不稳定 Conduction Electrons & Holes : to Conduction band (f ) → Valence band (HT #) left electron - hole • e jumps • é loses E. back into hole → recombination ↳ electron / hole current A m ible and las ime 2nd hole and Add When a les dones bright seeing the he Conductor / Semiconductor/Insulator : • 纯 半导 非良导,亦非良绝 Energy Conduction bund Conduction band Vilence band Energy gap Valence band Valence band Condiction and Overlap Insulator (b) Semiconductor (c) Conductor ~ pair Energy Conduction band electron? Energy gap energy Hole Valence band a L Electron-hole pair
ページ20:
Intrinsic 半导 Doping add Extrinsic 半导 impurities ↳ free c hole ft/ n-type : + pentavalent atoms (5A) -type ↳ e(majority carriers) p-type : 4 Diode : + trivalent o (majority carriers) o (minority carriers) atoms (3A) e (minority carriers) Depletion region (耗尽/空乏区): ions pn junction 附近 + - 耗尽e o . • barrier potential (V3). — 使穿过电场之ˇ ↳ 25°C Si 0.3 V / Ge →> 0.7 V L junction Temp ↑ Biasing a diode: (偏压) Forward bias (順偏): 允许 current Vants source n-type + 5A P-type - + 3A p region Depletion region n region (a) At the instant of junction formation, free electrons in the in region near the pu junction begin to diffuse across the junction and fall into holes near the junction in the p region. (b) For every electron that diffuses across the junction and combines with a hole, a positive charge is left in the s region and a negative charge is created in the p region, forming a barrier potential. This action continues until the voltage of the barrier repels further diffusion. Barrier pregion +V-region Depletion w VBIAS 才能导通 ⇒克服后,外加V provide n region e E a depletion region 对 Si导通发生于约0.7V , once 顺向导通, 二端V 几乎 在 remain V2在空区 effect => forward bias oppose Reverse bias (達倫): 阻止 current VBIAS source 接P carriers 远离pn junction 空乏区// 初期有 transient Current (瞬态电流,很快消失 最终大 多 I 停止 凵逆偏 空乏区宽, CV(Depletion - region Capacitance) . junction Temp 1 =>> 反向电流, ( PR J mA ~ nA $2) Reverse Breakdown : & # * of occur ①外部逆偏ˇ足夠大 少数 enough E 碰撞 atom 游离 价e 被撞入导带 ===> avalanche effect (雪收左) => 反向电流加 @ normal diodes 可能损坏 Zener diode (齐约二极体专为此设计)
ページ21:
Characteristics: General diode V-I characteristic curve symbol Anode (A)- " Va (breakdown) % Reverse bias Metal contacts and wire leads 1R Forward bias Barrier potential (Vg) VIAS VF VIAS + VBLAS Cathode (K) (b) Forward bias (c) Reverse bias . ideal diode Ideal diode model VF IF IF 1=0 (a) Forward bias (b) Reverse bias diode Rectifiers : (整流) 单向特性。 AC DC voltage 1. Half - wave rectifier: Operation during positive alteration of the input voltage I-BA Operation dringegative aeration of the input voltage average value Vag Vp 兀 vvv ww Ideal diode model Ideal V-/ characteristic curve • effect of barrier potential: Vp cout = Vp (in) 0.7 V • Peak Inverse Voltage (PIV) 逆偏时diode能承受最大 2. Full - wave rectifier: ... Vin 0 = 2 Vp 兀 Full-wave 0.637 V Bridge rectifier Full-wave Vout 0- rectifier During hall-cycle of the input. D, and Dward-hi During negative half-cycle of the input, D, and D, forward-biased and conduct an A PIV R center tapped full-wave rectifier V=Vi
ページ22:
Power Supplies •m mm mm mmm Hall-w Full-wave rectifier Load Capacitor - Input Filter : Rectifier 0- Filter 0 (a) Initial charging of capacitor (diode forward-biased) happens only once when power is turned on. RL " (b) The capacitor discharges through R, after peak of positive alternation when the diode is reverse-biased. This discharging occurs during the portion of the input voltage indicated by the solid dark blue curve. . PIV - 2V = • Ripple Voltage : (a) Greater ripple means less effective filtering. (b) Smaller ripple means more effective filtering. V r - ) 100% Vp L ripple factor special purpose diode : diode (LED): C: ½ cycle charge #discharge 0 Ripple Same slope (capacitor discharge rate) 0 (a) Half-wave Ripple mmmm (b) Full-wave ~ heat ligh Light 1. light - emitting 导带e 较价带 ○ 高能阶 recombination Energy 半导体 有大面积暴露 pn junction let # 7 th Visible 2. Photodiode Radiated light (mW) . (A) (a) Forward-biased operation (b) Typical light output versus forward current 感测光→ 电流 h == Imadiance, +++ ww ⇒ electroluminescence (****)
ページ23:
十五 Transistor (电晶体) DC operation of Bipolar Junction Transistor (BJT) : . npn (e-) / pmp (0) E(emitter,多数载子入) B (base) C (collector) bipolar 使用二种栽子(0) C (collector) Metalized contacts Oxide Emitter (base) Base Collector Substrate (a) Basic epitaxial planar structure (b) npw transistor Biasing : E (emitter) Base-Collector junction Base-Eminer junction BE junction -> 順偏 BC junction ↑ B B (a) npn (c) pmp 逆偏 transistor . IE Current: = IC + IB ↳ BDC : Voltage : I₁₁ = PI (IN = α DC = BDC= I₁ = IC ) LE transistor V₁ = V₁.-I.R. . V₁ = (a) p w BC reverse BE forward- biased C B E (b) pnp (b) pap BC biased ww BE forward- C E (PC:20~200) (a) mp (b) pnp => VE + VBE (VE=0 = √ ₁ = 0·7 V) Voltage - Divider Bias : +Vcc . RIN = B.RE - R₁ BJT Class A Amplifiers W R₁ Rc R₁₂ RE transistor full 导通 cycle (360) A low- - power (<IW) collector characteristic curves : VaB www (a) Circuit Rc www 0.7 V (b) le versus VCE curve for one value of Ig VCE Vctimas Ins IBA Ja 182 781 Catego 8-0 (c) Family of le versus VC curves for several values of In etc.)
ページ24:
I CEO (Ce) → ° Cutoff (open) BE:逆偏 BC:逆偏 达到VCE (sat) In ≠ Pae Is (即便I ^, I也不再7) Saturation (short) BE:順偏 BC: 順偏 Load Line operation Load line 截止、饱和点连线 (在线上工作) . Q - point DC load line To base current curve 交点 Ic Saturation (saturation) (Q-point) (Q-point) ol V Signal (AC) operation BAC = I. I Signal Voltage Gain. A₁ = R Av L V₁ V₁ Signal operation V₁ 4-0 Voe Cutoff of Amplifier : I. Re Rc = Ve I.RE RE Rc. RE Load line : on 4 mA Saturation 0 Cutoff 80 μA 70 μA 60μA -50 μA 40 μA 30μA 20μA 104A VCE VCE VCE (Q-point) 24 V (cutoff) +Vec R Re Rc $ I W • W Voc R₁ 10 k +24 V R₂ 2.7kf Re 4702 VCE RE 220 Bypass Capacitor Vout = IRc Common Emitter (CE) Amplifier - : Voltage Gain Vin = I₂ (r₂+ RE) increase j V₁ Rc C o Output • Bypass Capacitor Bypass Capacitor Av 25mV A₁ Vout 1.R. R₁ Input Output coupling capacitor = Vin I. (r.+ R) r₂+ RE Input coupling capacitor R₂ RE R₁ C₁ Bypass capacitor = (short RE) r. re x I.
ページ25:
RC RC: series Summary of Phonor RC parallel: V₁ R.L. RL series X 9 N Z e N P gs by on Vand in phase Ampliades depend the p I₁ I total B₁ ☑ Vs VR Vo RL parallel 8 8 V₁· VR · V₁ I I total 3 BL Y
ページ26:
2. Find VA and VED. 1.0 k ww B 100 V 1.0 k ww R₁ w 102 Rs www R₂ D 330元 V₁ => A→ # C 1.0 k VA C 1.0k www 33 R₁₂ WWW VED 33.2. 1+1 = √₁ ( 17 ) = 100 ( 141 ) = 50√4 VE-V₁ = -50-E25)=-25√A ww B D )x3 = 1.356 Roy 9.04 my V 1.356 D √TH = 102 16.5 16.5 + 10 + 10 RTH = 16.5×20 = 9.041 165-20 R 33 R RR 42.04| I 356 0.032 = R₁ = I₁ = Iq = √4 = 3 31 33 +10 + 10 = 3 3 = 0.097 0.032 0.032 x33 = 1.056 4241 √40-03233 -1.056 I₁- 0.032 1. Sine wave A has a positive going zero crossing at 30° from a reference. Sine wave B has a positive going zero crossing at 45° from the same reference. Both have peak values of 15 V. (a) Draw these two waves. (b) Determine the phase angle between the two signals. (c) Which signal leads? (d) Write the general expression of these two waves. (e) Find the instantaneous values of both waves at 90°. (A) The capacitive reactance is jóv R www 2.2 k f = 1.5 kHz (b) 45° -35° = 15. A: 15 sin (e-) B v = 15 sin (8) (C) A C Determine the current through R, and R, for VAB=6V R₁₁ www R₂ 3.3kf 2.7 k R₁ R₁ 10 kn 9 B w 4.7 kf Rs 4.7kf (c) A A V= sin 0.87 B V = sin .71 R₁ 0.022 uF Determine the voltage gain of the amplifier in Figure 19 both with and without a bypass capacitor in normal and in decibel form. V₁ = (RRR) Vec R₁ = (47 +10) 10 = 1.75 √ Vec +10V ZATER S ov 2πfC 2(1.5 kHz)(0.022 uF) - 4.82 k z=VR²+ X = √(2.2 km2)² + (4.82 ks)² = 5.30 k 1 1 Xc= The impedance is Applying Ohm's law yields V Z 10 V 5.30 k 1.89 mA V₁ = √₂ - 0.7 = 105 V I₁ = V 1.15 1.05 mA R R 10kn X= 25-V re= I₁ 25 1.05 23852 A₁₁ = R₁ + RE 4.7k 1023.8 -4·58 Ay = 20 20 lg (4-591-13-2483 R₁ r A₁ = 11-m 197 Ay = 20 23.8& 20by (197)-45-928
ページ27:
Generator : AC 有刷: 集電環 定子 轉子 電刷 DC 有刷: 换向器
おすすめノート
このノートに関連する質問
Undergraduate
工程與科技
電路學 求解這兩題
Undergraduate
工程與科技
請問這題的解法~謝謝
Undergraduate
工程與科技
靜力學 求出E, F的N, V, M 拜託了🙏
Undergraduate
工程與科技
這題有沒有可能只用反函數就可以解出來⋯ 為啥算不出答案,ㄚ。
Undergraduate
工程與科技
這是一題單純的R與C並聯,Z是並聯後的阻抗,請問Rx和Cx怎麼推導
Undergraduate
工程與科技
電子學問題-小訊號分析 想請問有人能幫忙解答如何畫出此題的小訊號圖嗎 自己畫出來的差一個負號🥺 感謝🙏
Undergraduate
工程與科技
靜力學求解
Undergraduate
工程與科技
請問8~13要如何計算?
Undergraduate
工程與科技
想請問這題該如何解呢?
Undergraduate
工程與科技
程式錯誤 請問該如何修改?
News

コメント
コメントはまだありません。