ノートテキスト
ページ1:
SISTEM Persamaan 1. Dua Variabel (SPLDV) • Eliminasi 2x + y 3 x 1 X = 8 1x1 2x+y=8 = 1 1x2 2x-24-2. g = 3 LINEAR 12x+214 = -3 112x + 204 = 12 y=-1511 3x+5(-5)=3 39=6 y=2 3x-75 = 3 ca + 3 = 5 1 0 = 2 X 211 b 1 = 2 4) 3 2x+5y+3 3x-2y-2 3 = 1- 2x+5y+3 3x-2y-2. • Subtitusi 2x+4=8 x = 4 = 1 x = 1+y 2(179)+y=8 2+2y+y=8 3y =6 y =2 Eliminasi Subtitusi 2x+2-8 2x = 6 XX = 26 3x=78 × => =2611 y = -15 $ 11 misala = 1 2x+54 +3 x = 3. 2) 1×11/14 = 11 x 6 b = 2x+y=8 x-4=1+ 3x=9 x = 3 HP = (312) 3-y=1 2=y 12x78y = 24 9x-8y = 60 + 21X =84 ✗ = = " 3(4)+29 = 6 +36 = 1 36 = 2x-4 = 5 x12 3x+2y=6 9x-8y =60 1×4 9 +39 = 1 30-66- 29+66=2 59- = 2 3x-2y-2 39-66= = 2 2 + 2x+y=8x04 (0,8) 480 (410) x-4-1×10/0 X0-1 (0,1) (-1,0) 6. 4- > HP (3.2) 2- 246 = Grafik Contoh 1) 4x + 7y+1=0 ×3 3x + Sy-3=0 1 x 4 X 12724 = 6 2y= =-b y=-311 (4-3) 3) ½ + ½ = 5 + 13 = -5 onisal: a.b b == a = → 1 = 2x+54+3 2x+5y+3=2 =2x+5y=-11x3 b = 6 = y j = a+b=5 ×2 29- -36=-5 XI 29 +26=10 2a-3b=-5 sb = 15 b=3 <- 1 3x-2y-2 3x-2y-2=6 =3x-2y=81×2 6x+5y=-3 6x-44=16 194-19 y=-1 2x+5(-1)=-1 2x-5=-1 2x = 4 => x=2/1
ページ2:
12. TIGA VARIABEL (SPLTV) # 9. 2 39-404) 30 20 P&P 2x + 34-2-5 *+ 4+2 = 9 3. 39 + =0 4) 2x+4y-6-32 x-3y=-7-27 × = 24 +2 = -5 = 3 4 J 2x +44 +32=6 2x + 3(3) =2 22 x-3y+22=-7 2x + 1 = 2 X- 2y+2=-5 + 3x + 4y P&P = 14 - Y 2x =1 X = x-3y+22=-7 x + y + z = 9 31 X3 x-24+ z = -5 -y+z --2 x-24-2 =-7 + 2x-y =3 P&Ps 3x+44 = 14 x1 2x-9 = 2 x4 3x + 4y = 14 8x-49 = 8 IX ✗ 212) - =22 = 211 2 = 2 4-4 y = 211 x + y + z = 9 2+2+2=9 4+2=9 z=511 Hp (2,2,5) 2) 2x + 3y = 2 ... 1 -x + 4 + + misal a D 2x +44 +32=6 2x - by +62 =-14 109-32 = 20 -3y+32=-6 -104-32 = 20 a = x, b = 1/1, c = /== + = 14 y = 2 29 +26+30 = 4 × 9 +4b-4c = 0x21x3 39 +36 +20=1 20+2b+3c=4 29+0b-8c=0 - 74 +2+2 = -2 × 1 2 bb + c = 4 1×3 39 +12b-12C = 0 3a+3b+20=1 9b-14c = -1 1x2 -18b433c=12 18b-28 C = -2 SC = 10 C = 211 + 1 z = " x-2(2)+1=-5 ✗- 4 +1 =-5 x-3=-5 x= -2 x + 2z = 1 2 3y +8=3 3 -bb + 11 (22) = 4 -6b+22 2x+3y = 21×1 x+27=1x2 2x + 3y = 2 2x + 42 =2 34-42=0.4 3y+87=3 3y+42=0 122=3 2 = 1 =4 -6b=-18 b = 311 at 4(3) 4(2) = 0 9+12-8=0 a+4=0 a = -4 -> = a = -411 1 - b = 3 -> C = 2 = C C C C
ページ3:
A (27) -> 7-a (2)²+b.2+c 7=4a+ab+c... (1) B(-67) 7 = 9 (-6)²+ b (-6)+c 7-360-6b+ C ... (ii) c (10) > 0 = a()" + b (1)+c o= a+b+c... ii) Tentukan persamaan parabola mempunyai nilai b untuk x = 0 dan x = -2 dan nilai max = 8 0+ (0)9+ (0)109 <- (910) (i) 7 7=4a+ab+c) 7=3(1)+b 7=369 +66 +C 7=3+b b = c (-2,6) -> 6 = a(-2)+ b(-2)+6 0-49-2b2 0=29-b 0 = -320 +86 :8 4-b11 0 1 -qa+b (iv) Yp = b²-4ac 8 0=1+4+c ya b=29 -21-2) i 7 = 40+2b+c fff 0 = a + b + c ==411 v 7 = 3a+b (V) 0=5+0 -5=4 y=ax fbx+c =(1)x+(4)x+(-5) x2+4x-511 [V 0=-49+b 7 = 39+ b -7--79 1 = a, + P(xp.Up) yp = nilai max/min (α<0) (a>0) -b Xp Sumbu Simetr = →>> 20 == Contoh 1) Tentukan Persamaan Parabola melalui (0,5) (2-3) dan Sumbu simetri 3 (0.5) -> 5 = 9 (0) + 6 (0) +c 5=C1 (2,-3)-3=a (2)+6(2)+5 -3=4a+2b 15 -8-49+26 = 2a+b : 2 -4= Xp. b. = 3 20 b =-69 -> b=-6(1) b = -6. -4=29-6a -4=-49 1=91 Y = 1.x + (-6)x+5 =x-6x+511 (201)-4 (9, (6)-8 -4(a) 4a-249 =-320 (4=(-2)x+(-4)x+6 4a² + 8a=0 4ȧ (a+2) = 0 C = O (TM) 9=-211 Menggambar Kurva 4 = -2x²-4x+6 = -2x-4x+b1 Cari titik potong sbx -> y=0 0 = -2x²-4x+6 x2+2x-3 (x+3)(x-1) x ==3->(-3,0711 x = -1 -> (10) // :(-2) ii) Cari titik potong 864 → x = 0 = -2(0)2-4(0)+6 y = 4-6 1016111 iii) Can titik puncak (Xp, Yp) Xp = -1-4) 4 = 2(-2) -2 -1 Yp=-(-4)-4(-2)(6)= 16-198 -4(-2) 1 8 41-118) 64 = 8, iv) Titik Banky > misal; ctnhik -45×52 X-4-228 (-4,-10) d (2,-10). 4-106-108 (-2,6) (-4) - y=-2(-4)2-4(-4)+6 =-32+16+6 = -10
ページ4:
| (11) > y = -2(-2)+4(-2). (2) Kurva 19 = 8+8+6 →>9=-2(2)-4(2)+6 E -8-8+6 9==10 19 6 -10 2 -4≤x 10 -4<x 0 Bentuk umum x = ay² + by +c axo (-) 970 (4) > cccc c c c c
他の検索結果
おすすめノート
Fungsi Kelas 10
1137
3
[UTBK] Kuantitatif
1101
5
このノートに関連する質問
Senior High
Mathematics
guys siapapun bantu jawab
Senior High
Mathematics
bantu aku selesaikan soal ini
Senior High
Mathematics
tolong kasi jawaban dan penjelasan nya
Senior High
Mathematics
tolong kasih tau jwbnya
Senior High
Mathematics
tolong buatkan materi dari kisi-kisi tersebut untuk latihan ujian tka
Senior High
Mathematics
Jelaskan saya sampai saya bisa
Senior High
Mathematics
Jelasin saya sampai saya bisa
Senior High
Mathematics
tolong kerjakan
Senior High
Mathematics
bagaimana caranya paham matematika dengan cepat pliss.. beritahu aku dong siapapun
Senior High
Mathematics
Enroll in CEH Training in India and gain hands-on experience in ethical hacking, penetration testing, and cybersecurity tools through instructor-led sessions, practical labs, and career-focused learning designed for beginners and professionals. https://www.siemxpert.com/ceh-training-in-india.html
News
コメント
コメントはまだありません。