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TOEIC・英語 大学生・専門学校生・社会人

文章を読んで上の1〜4の問題を解くものです。 分からないのでお願いします

3. Answer the following questions. 1 What is the difference between UNIX and Linux? 2 3 4 Choose one of the words in italics in the text. What is the definition of the word you have chosen? What are the three levels of a Linux system? What are the two main functions of the kernel? [Reading Text] UNIX was initially developed by researchers at Bell Labs in the 1970s. Today, UNIX and its variants are widely used mainly on servers. By far, the most well- known UNIX-like operating system is Linux. Linux is available in different distributions which include the Linux kernel and different collections of software. These distributions have various user interfaces, many experienced users preferring the command-line interface, or shell. Linux distributions include a range of software including text editors. memory. While the mechanics of Linux and other Unix operating systems are complicated, the components of a Linux system can be grouped into three levels. The lowest level is the hardware, such as Central Processing Unit (CPU) and The next level is the kernel. It enables communication between hardware and software, by providing instructions to the CPU and other hardware. The programs that are running on the system, or processes, make up the top level known as the user space. Processes in user space generally only have access to a restricted amount of memory and operations, this is called user mode. The kernel runs in kernel mode which allows it unrestricted access to hardware resources. The kernel provides functions such as process management and memory management. A computer only has limited Random Access Memory (RAM) and processor cores. Process management allows the system to run multiple programs (processes) at the same time even if the CPU can only execute only a few processes at a time. Memory management allows applications to share the system's memory while avoiding potential issues such as memory leak. Included with the kernel are device drivers that provide an interface for applications to communicate with hardware, such as hard drives. System calls allow user processes to access features that are executed at kernel mode, for example creating new processes.

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TOEIC・英語 大学生・専門学校生・社会人

この1〜4の問題お願いします🙏🏼🙏🏼

3. Answer the following questions. 1 What is the difference between UNIX and Linux? 2 3 4 Choose one of the words in italics in the text. What is the definition of the word you have chosen? What are the three levels of a Linux system? What are the two main functions of the kernel? [Reading Text] UNIX was initially developed by researchers at Bell Labs in the 1970s. Today, UNIX and its variants are widely used mainly on servers. By far, the most well- known UNIX-like operating system is Linux. Linux is available in different distributions which include the Linux kernel and different collections of software. These distributions have various user interfaces, many experienced users preferring the command-line interface, or shell. Linux distributions include a range of software including text editors. memory. While the mechanics of Linux and other Unix operating systems are complicated, the components of a Linux system can be grouped into three levels. The lowest level is the hardware, such as Central Processing Unit (CPU) and The next level is the kernel. It enables communication between hardware and software, by providing instructions to the CPU and other hardware. The programs that are running on the system, or processes, make up the top level known as the user space. Processes in user space generally only have access to a restricted amount of memory and operations, this is called user mode. The kernel runs in kernel mode which allows it unrestricted access to hardware resources. The kernel provides functions such as process management and memory management. A computer only has limited Random Access Memory (RAM) and processor cores. Process management allows the system to run multiple programs (processes) at the same time even if the CPU can only execute only a few processes at a time. Memory management allows applications to share the system's memory while avoiding potential issues such as memory leak. Included with the kernel are device drivers that provide an interface for applications to communicate with hardware, such as hard drives. System calls allow user processes to access features that are executed at kernel mode, for example creating new processes.

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物理 大学生・専門学校生・社会人

力学の問題です。回答だけでもいいので教えていただきたいです!!

質量mの物体を水平面と0 (ただし, 0 0 < ™/2) の角をなす方向 に速さで投げ上げた. この物体の運動を調べるために, 水平方向で 物体が進む向きを を設定する. このとき, 時刻における物体の位置と速度をそれぞれ ((ty(t)), (x(t), ey(t)) で表すことにして, 時刻t=0における物体の位 置は (x(0),g(0)) = (0, 0) であるとする. また, 空気抵抗は無視できてこ の物体に働く力は重力 mg =-mge のみであるとして, 以下の問いに答 えよ. (1) 運動の様子を図示せよ. 物体に働く力も記入すること. (2) 方向と方向それぞれの運動方程式を立てよ. (3) 速度の成分v(t) とy成分y(t) を求めよ. (4) 位置の成分ェ(t) とり成分y(t) を求めよ. (5) この物体が最高点に到達したときの水平面からの高さを求めよ. 解答群 (1) (a) (c) (b) 0, mg (2) (a) mgsin0, mg cos0 鉛直上向きを+y方向とする座標系 方向とし, dvx dt mg cose mg sin 0 dvy (c)m =mgsino, m=mg cos0 dt (5) (a) (b) .mg (c) (d) X =-mg (b) dvr dvy (d) m- = 0, m- dt dt (3) (a) vェ(t) = vosin0, vy(t)=-gt + vo cos 0 (b) x(t) = vot cos0, y(t)= vm sin (20) g sin A cost 2g sin20 2g vcos²0 2g (d) (b) ux(t) = up cos0, vy(t)=-gt+vo sin 0 0 (c) ux(t) = gtsin0, vy(t) = - gt cos0 + vp sin 0 (d) ux(t) = gt cos0, vy(t) =-gtsin0 + vp cost y (4) (a) x(t) = vot sin0, y(t) = -12gf2 + vot cost y(t) == /2gt² + 0 (c) x(t)=1/2gt-sino, y(t) = -12gt-cos0 + vot sin0 1 (d) x(t) = ½gt² cos0, y(t) = −gt² sin + vot cos + vot sin 0 img sino mg mg cos e x x

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物理 大学生・専門学校生・社会人

力学の問題です。全然分からないので、画像の選択肢の答えだけでもいいので教えていただきたいです。

5. 上空から落下する雨滴を質量mの質点とみなし, 鉛直下向きを正の方向 (+2方向)として, その運動を考える. この雨滴には,重力 mg が働くと ともに,速度v=žに比例する粘性抵抗力 (av) が働いている.ただし, gは重力加速度の大きさ る雨滴の速度と位置をそれぞれ (0) = 0, 2(0) = 0 とする.このとき,以 下の問いに答えよ. (1) 運動の様子を図示せよ。 雨滴に働く力も記入すること. (2) 運動方程式を立てよ. (3) 時刻t における速度 v(t) を求めよ. (4) 終端速度 vv = lim v(t) を求めよ。 また, 終端速度に達しているとき には,雨滴に働く力はどうなっているといえるか? 解答群 (1) (a) (c) (2) (a) mg - av (d) m (3) (a) v(t) do dt (c) v(t) = いえる. (4) (a) v = える. == a = -mg+av mg a mg (b)uxo = - mg α mg a mg -αU t = 0 におけ は比例定数である.また,時刻 mg av ym g (b) (d) dv (b) -mg + av (c)m = mg - av dt mg O a (1 - e-t) (1-et) (b) v(t): mg (1+ent) (d) v(t) = ² (1 + e²²) α -dv m.g -αu mg これは定数なので雨滴に働く力はつり合っているとい これは定数なので雨滴に働く力はつり合っていると (c) um = ∞. 終端速度は無限に大きくなっていくので,雨滴には重力 のみが働いている. (d) um = -∞. 終端速度は無限に大きくなっていくので,雨滴には重 力のみが働いている.

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