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TOEIC・英語 大学生・専門学校生・社会人

67の答えがCなのですがおかしくないですか?恐らくCEOの事を書いているのだと思いますがCEOと社長presidentは別の役職で同じではないと思ったのですが

65-67 refer to the following conversation. W: Richard, we were deeply impressed with your presentation this morning. You concentrated on the benefits the customers 65. What did the man do this morning? OEIC (A) He had a talk with an executivetsTENING will get from our new products. That was awesome. The sales manager wants you to give a presentation on the same topic to the board of directors next week. (B) He gave a talk. (C) He made a presentation to the board of directors. (D) He put together handouts. 66. What does the woman suggest? I'm glad you liked it. I'l try my best to please the board of directors. Maybe l could use some technology to supplement my presentation. Don't you think using a video allows the audience to understandit (A) Preparing more informative materials (B) Using a video (C) Getting advice from the sales manager (D) Choosing a new topic M: ,Com, /。 better? W: That's a good idea. You should prepare more extensive handouts as well. I will be free this afternoon, so l can help you put them together. M: I'd appreciate it. Let's make it our top priority to ensure that our executives are satisfied. Even the CEO will be there. 67. What does the man say about next week's presentation? (A) It will take place in the afternoon. (B) It will concentrate on the benefits of video presentations. (C) The president will see it. (D) The sales manager will help them prepare for it. 65B 66A 6

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化学 大学生・専門学校生・社会人

熱力学について質問です。 問題文の一定の外圧1.00atmをどう扱ったら良いかよく分かりません。自分でとりあえず解いてみたんですが合ってる自信あまりないです。もし分かる方いらっしゃいましたら、ご教授していただけませんか?🙇‍♂️

Problem 2 A sample consisting of 1.00 mol of perfect gas molecules at 300 K is expanded isothermally from initial pressure of 3.00 atm of a final pressure of 1.00 atm against a constant external pressure of 1.00 atm. Determine the values of q, w, AU, AH, AS, ASsur, and AStotal. 300Kにある完全気体 1.00mol の試料が、 温度一定で始めの圧力 3.00 atm から終わりの圧 カ 1.00 atm まで、一定の外圧 1.00 atm に抗して、 膨張する。 この過程に対して、9, w, AU,AH, AS, AS r, ASiosal を求めよ。 管品可運勝張より、Tが喫化しないためるリ=D 始めの体様をV終わりの体殊をソュとおくと. V, = 8.314× 300 スH- AU + PAV 1660 [コ] 1660 8.21×(o°[m] AS = = 5.53 [h] 300 ニ 3×1, 013 × /D" Vz = 8.314x300 1.013× [0 外界が理た熱置はdisur = -AHよ) = 0.0276 [m] ASsur- 「desur T 1660 300-5.53[7h] Pdv = -1.013 x /0°x (0.0246- 8.21Y16') - こ M AStotal こ AS + ASU- = -1660 LJ] AV= 9+ W より 1 - -w- 1660[5] 0 Problem 3 Calculate the change in the molar entropy at 1 atm when a solid ethanol at 159 K of the melting point changes

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