英問英答の問題です。この英問に対して線を引いたところが答えだと思ったのですが、答え方がわかりません。わかる方お願いします🙇‍♀️

weaknesses. // 弱さ could be reached, / no matter how high / it might はずだ 8 到達する どんなに高くても Marin is now preparing/ for her next adventure. ⑦ She hopes to sail/to 準備をしている 航行する 人生 various countries / with a human-powered yacht / and talk about life and the さまざまな 人力の ヨット future / with children there. // Marin says,/ “To live is to weave your tapestry/ こと 生きる ベストリー 現地の を編む with different patterns. // The patterns and colors in our tapestries are さまざまな 模様の 模様 determined / by how we live. // ⑩ We need / to ask ourselves / what we want to 決められる 私たちの生きが たずねる do / in order to make / our own special tapestries." // 何をしないのか 自身 するために m TE 特別な (tous all: / “Even though your steps may seem th

（1）がわかりません。 答えは4.0sの時なのですが、AとＢの速度が一緒になった時になぜ距離が最大になるのか分かりません。

思考 27.2 物体の運動 物体AとBが,図のv-tグラフ のような速度で, 一直線上を動いている。 時刻 t=0s のとき,両者は同じ位置にあったとして,次の各問に 答えよ。 (1) 0≦t≦8.0s の範囲において, AとBの間の距離 が最大となる時刻は何か。 ↑v[m/s] 8.0 2.0 0 A 4.0 B (2) 0≦t≦8.0s の範囲において, AとBの間の距離 が最大のとき, その値は何mか。 (3) AがBに追いつく時刻 tは何sか。 (4) 0≦t≦8.0s の範囲において,時刻 0s での位置からの移動距離 x[m〕を縦軸,時刻 t[s]を横軸にとり, A, B の x-tグラフを1つの図にまとめて描け。 (岐阜聖徳学園大改) t[s] 8.0

最後のWe must 〜の一文で訳は、 私たちは、注意に対して錯覚することが あるのだということを認識することによってのみ、 見なくてはいけないものを見逃さないための 対策を取ることができるということを 覚えておかなければならない。 となるのですが、文構造が分かりません... 続きを読む

IWC MINUTistall the mints of technology, these alus can actually make us less likely to notice what is around us. We must remember that only by 気づきにくくさせる 覚えておく becoming aware of our illusion of attention can we take steps to avoid missing we need to and blow auo to stosque 998 sw ylhivi word word ow bavors anitasits to auoot wo to abiejuo Het teds blow wo to adoqas esodi to eiswamu yleislamos see. Savua 00. what ees I a

Darius still (B) keeps the sewing machine in his mom's apartment busy with his work. 「ダリウスは,今でも母親のアパートのミシンで蝶ネクタイ製作にいそしんでいる。」 という文章についてです... 続きを読む

3はwhichでは罰ですか？

whoeyer / anyone yon is having 2 例にならって下線部の誤りを訂正し、文全体を書き直しましょう。 (15) My father always keep my promise. → My father always keeps his promise. (1) Iwant to ask for the opinion of someone which is familiar with the law. nove to ask for the opinion of someone who is kamiliar with the law (2) I looked up which I wanted to know in the encyclopedia. what I wanted to know in the encyclopedia I looked up (3) The report mentions something what is important to our lives. The report mentions report mentions something the attever is important to our lives. 1 (1) This is the picturun which Allem in S.

下線部の誤りを直してほしいです！

2 例にならって下線部の誤りを訂正し、文全体を書き直しましょう。 (15) My father always keep my promise. (1) Her dream is work for world peace. (2) I like run in the park before breakfast. (3) The driver practiced to park her car. → My father always keeps his promise. (4) She is good at to teach math. sdmsm

4問とも下線部の誤りを直してほしいです！

2 例にならって下線部の誤りを訂正し、 文全体を書き直しましょう。 (15) My father always keep my promise. → My father always keeps his promise. (1) My cousin has games as many as you have. (2) My uncle drinks tea as many as an Englishman does. (3) This milk is not as fresh as that one. (4) Emma can run faster than any other boys in her class.

4問とも答えを教えてください！！

2 例にならって下線部の誤りを訂正し、文全体を書き直しましょう。 (15) My father always keep my promise. → My father always keeps his promise. (1) My car is cheaper than you. (2) The tail of this dog is longer than my dog. (3) It is very hot today than yesterday. (4) He looks tired than he was last week.

3なのですが、whatはなぜ間違いになるのですか？

1 内から適切な語句を選びましょう。 (1) That's (which / what) you said yesterday. (2) Are animals (who / that) are in zoos happy? (3) There are three employees (that/whom ) will receive an award. (4) The apartment house, (which / whose) bathrooms are shared by the residents. repaired next month. what he was (5) He is not (that/ what ) he was. (6) Who was the person (to who /to whom ) you spoke yesterday? 3 日本 (1) 私が欲し The camera 過去の彼 is (2) I looked up which I wanted to know in the encyclopedia. I looked h (2) 私は昨日、友人と I met a friend o (3) 始まりがあると Whatever (4) 彼女はいわに She is (5) その木は変 The tree, again ne (7)/Today I didn't see the boy and his dog (which /that) run in the park every day. that (8) This is the pen (with which/with that) the novelist wrote his novels. (9) He said that he could speak English) ( that / which ) was a lie. (10) If (wh whoever / anyone ) is having difficulty hearing me, let me know. 2 例にならって下線部の誤りを訂正し、文全体を書き直しましょう。 (151) My father always keep my promise. → My father always keeps his promise. (1) Iwant to ask for the opinion of someone which is familiar with the law. kamiliar with the lan of someone who want to ask for the opinion. what I wanted to know in the encyclopedia 4 日本語の (1) 京都 Kyo (2) 15 N up (3) The report mentions something what is important to our lives. The report mentions something that ever is important to our lives (4) This is the picture which Allen is proud. This is the of hoch Allen is picture proud (5) I learned the procedure from him, who was a mistake. (I learned the procedure from him), which was a mistake (3) (6) He, which father is the president of the company, got promoted. He, whoes father is the president of the company, got promoted (7) Whoever win first prize in the contest, it matters little to me. wins Whoever work dirst prize in the contest, it matters little to (8) Which is more, they revealed an unexpected finding. What is more, they revealed an what is more this whoever i 66 unexpected finding unexp

なぜRの遺伝子頻度の求める計算で分母の数を✖️2してるか分かりません。教えてください。

手順 STEP 4 と同じ記号を使っ 男性の中で赤緑色覚異常が1% (=0.01) なので, 228 g=a p=1-a=b 女性保因者は XX' という遺伝子型なので, その比率は 2pg である。 よって女性 (これを100%とする) の中での保因者の 頻度は,2×a×b=c となり, %で表すと dとなる。 STEPS 遺伝子頻度が変化する場合をマスターしよう (1) ある植物で種子の形について丸 (RR と Rr) が 84%, しわ (rr) が 16% を占 める集団があるとしましょう。 R, r の遺伝子頻度をそれぞれp, g(p+g=1) とすると, ∴.p=1-0.4=0.6 RR: Rr: rr = p2: 2pgg' から、g2=0.16 g =0.4 となり,ハーディ・ワインベルグの法則が成り立てば、この遺伝子頻度は代 を重ねても変化しません。 (2)では,この集団からしわの個体をすべて除いて, 丸の集団の中で自由に交 配させると,次世代の集団の遺伝子頻度はどうなるでしょうか? p = 0.6g = 0.4 なので、 残った集団は, この集団での遺伝子頻度を求めます。 RR: Rr = p2 : 2pg=0.62 : 2×0.6×0.4=0.36 : 0.48=3:4 Rの遺伝子頻度は, f 2 四 3×2 +4×1 5 ( 3 +4)×2 7' よって, R:r=52 これが自由に交配するので、次の世代は, = 5R 2r 25RR 10Rr 4rr 5R 2r 10Rr a : 0.01 b: 0.99 rの遺伝子頻度は, c: 0.0198 d: 1.98% RR: Rr: rr = 25:20:4 よって, この新しい世代の集団でのR遺伝子の頻度は, 25 ×2 +20×1 (25+20+4) × 2 =0.714･・・0.71- 4×1 2 14 7 - もとは 0.6 だったのに